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zavuch27 [327]
4 years ago
9

Write the equation of the line given the slope = 11 and b=-2 with y = mx + b

Mathematics
1 answer:
romanna [79]4 years ago
3 0

Answer:

y = 11x -2

Step-by-step explanation:

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Need help with 1 & 2 anyone wanna help I will mark you brainliest
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1. First step: To get a term of x by itself, add 5 to both sides

Second step: This will become 3x<24

Third step: To separate 3x, divide everything by 3: 3x÷3 < 24÷3

Step four: x < 8

2. First subtract both sides by 12: - 2x + 12 - 12 < - 4 - 12

Second: This becomes - 2x < -16

Third: Divide by -2 to get x by itself - 2x ÷ - 2 > -16 ÷ - 2 Note: If you divide by a negative number, the inequality sign switches. This is a really important step that most students forget.

Fourth: x>8

Note: Try plugging in values when you are done if you are uncertain you have the right answer.
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3 years ago
What is the interval notation for the following graph
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4 years ago
Factor this expression.<br> x2 + 9x + 8
Ket [755]

Answer:

(x+1)(x+8) When factoring squares whose squared coefficient is one the roots must add up to the coefficient of the slope and multiply out to the intercept value.

6 0
3 years ago
Tara stayed at the Merry Mountain campgrounds last weekend. She paid a rental
Nezavi [6.7K]

Answer:

she will pay $19 for each day

Step-by-step explanation:

94-18=76

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6 0
3 years ago
At what values of x does f(x) = x^3 - 2x^2 -4x+1 satisfy the mean value theorwm on [0,1]
denis-greek [22]

Answer:

x=1/3

Step-by-step explanation:

A function f is given as

f(x) = x^3-2x^2-4x+1 in the interval  [0,1]

This function f being an algebraic polynomial is continuous in the interval [0,1] and also f is differntiable in the open interval (0,1)

Hence mean value theorem applies for f in the given interval

f(1) = 1-2-4+1 = -4\\f(0) = 1

The value

\frac{f(1)-f(0)}{1-0} =\frac{-4-1}{1} =-5

Find derivative for f

f'(x) = 3x^2-4x-4

Equate this to -5 to check mean value theorem

3x^2-4x-4=-5\\3x^2-4x+1=0\\\\(x-1)(3x-1) =0\\x= 1/3 : x = 1

We find that 1/3 lies inside the interval (0,1)

4 0
3 years ago
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