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pochemuha
3 years ago
7

Need help with 1 & 2 anyone wanna help I will mark you brainliest

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
6 0
1. First step: To get a term of x by itself, add 5 to both sides

Second step: This will become 3x<24

Third step: To separate 3x, divide everything by 3: 3x÷3 < 24÷3

Step four: x < 8

2. First subtract both sides by 12: - 2x + 12 - 12 < - 4 - 12

Second: This becomes - 2x < -16

Third: Divide by -2 to get x by itself - 2x ÷ - 2 > -16 ÷ - 2 Note: If you divide by a negative number, the inequality sign switches. This is a really important step that most students forget.

Fourth: x>8

Note: Try plugging in values when you are done if you are uncertain you have the right answer.
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I rlly rlly need this badly, pls show work :(
elena55 [62]
1) 2x + 3y = 12 -> 3y = -2x +12 -> y = -2/3x + 4
2) 4y - 7x = 16 -> 4y = 7x + 16 -> y = 7/4x + 4
6 0
3 years ago
The product of two consecutive integers is 420 which quadratic equation can be used to find x the lesser number
Fynjy0 [20]

Answer:

Step-by-step explanation:

If the smallest number is 'x', then the other number = x +1

x*(x+1)= 420

Use distributive property

x*x + x*1 = 420

x² + x - 420 =0   ------> this is the required quadratic equation.

5 0
3 years ago
A designer is creating a rug for an oddly-shaped room. His design for the rug is shown below. If each blue square represents 1 s
likoan [24]

Answer:

btw we cant see the image sorry

Step-by-step explanation:

3 0
3 years ago
I'm pretty sure its D.
lidiya [134]
I hope this helps you




5=7x+0.1+10x-0.2


17x=5.1


x=5.1/17


x=3/10


x=0.3


7 0
3 years ago
What is the elimination method in math?
SSSSS [86.1K]

Answer:

In the elimination method you either add or subtract the equations to get an equation in one variable. When the coefficients of one variable are opposites you add the equations to eliminate a variable and when the coefficients of one variable are equal you subtract the equations to eliminate a variable.

Hope this helps!

If you need a more in-depth answer, don't hesitate to ask!

6 0
3 years ago
Read 2 more answers
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