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pochemuha
3 years ago
7

Need help with 1 & 2 anyone wanna help I will mark you brainliest

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
6 0
1. First step: To get a term of x by itself, add 5 to both sides

Second step: This will become 3x<24

Third step: To separate 3x, divide everything by 3: 3x÷3 < 24÷3

Step four: x < 8

2. First subtract both sides by 12: - 2x + 12 - 12 < - 4 - 12

Second: This becomes - 2x < -16

Third: Divide by -2 to get x by itself - 2x ÷ - 2 > -16 ÷ - 2 Note: If you divide by a negative number, the inequality sign switches. This is a really important step that most students forget.

Fourth: x>8

Note: Try plugging in values when you are done if you are uncertain you have the right answer.
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Kelvin finds a tile shaped like a triangle. He measures its angles to discover that it has two acute angles and one right angle.
Aleonysh [2.5K]

Answer:

right triangle

Step-by-step explanation:

A Right triangle is a triangle that has one of its angle as 90°.

Since the triangular shaped tiles has a right angle, the kind of triangle Kevin found will be a right triangle.

A right triangle has two acute angles (angles less than 90°) and a right angle

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3 years ago
Using the graph, determine the equation of the circle
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Answer:.

Step-by-step explanation:

Well if you look at the graph and first look at the

joe nuts

7 0
3 years ago
Find the side length of the largest cube which can fit inside a sphere of diameter 24 cm
ser-zykov [4K]
If the diameter is 24, the radius must be 12
√(3x²) = 12 

<span>3x² = 144 </span>

<span>x² = 48 </span>
<span>. . . . ._ </span>
<span>x = 4√3 
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</span>
Hope this helps 
7 0
4 years ago
Aryan wants to plant a flower on the ground in the form of a rhombus. The diagonals of the rhombus measures 42 cm and 56 cm. Fin
Vlad1618 [11]

<u>Given</u><u> info</u><u>:</u><u>-</u>

Aryan wants to plant a flower on the ground in the form of a rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.

Find the perimeter of the field ?

<u>Explanation</u><u>:</u><u>-</u>

Given that

rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.

Let consider a rhombus ABCD

Let AC = (d1) = 42 cm

Let BD = (d2) = 56 cm

We know that

The digonals of a rhombus bisects each other at 90°.

AC = AO+OC

⇛ AC = 2 AO = 2 OC

⇛ AO = OC = AC/2

⇛ AO = OC = 42/2 = 21 cm

and

BD = BO+OD

⇛ BD = 2 BO = 2 OD

⇛ BO = OD = BD/2

⇛ BO = OD = 56/2 = 28 cm

We have,

∆AOB is a right angled triangle

By Pythagoras theorem,

AB² = AO²+OB²

⇛ AB² = 21²+28²

⇛ AB² = 441+784

⇛ AB² = 1225

⇛ AB = ±√1225

⇛ AB = ±35

AB is the length of the side which cannot be negative.

AB = 35 cm

We know that

All sides are equal in a rhombus

⇛ AB = BC = CD = DA

As we know

The Perimeter of a rhombus = 4×Side units

The perimeter of the rhombus ABCD

⇛ 4AB = 4BC = 4CD = 4DA

⇛ 4×35 cm

⇛ Perimeter = 140 cm

<em>∴</em><em> </em><em>T</em><em>he perimeter of the given field is 140 cm.</em>

6 0
3 years ago
Noah enlarged a photograph by a scale factor of 6. The area of the enlarged photo is _______ times as large as the area of the o
Ratling [72]

Answer:

Lets call the dimensions of the rectangle l and w. The new dimentions are 6l and 6w. The area of the first rectangle is lw. The area of the second rectangles is 36lw. 36lw/wl is the answer, and this is 36.

4 0
3 years ago
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