Ask question

Ask question

All categories

3 years ago

5

HELP ME PLEASE!!! Please answer my question that is in the comment. It is super urgent!!!!! I will mark your answer as brainlist

, I promise!!!

1 answer:

Lilit [14]3 years ago

6 0

Answer:

6

Step-by-step explanation:

If you simplify 15/25 it gives you 3/5

3/5 times 10 gives u 30/5 which is 6

Correct me if this is wrong

You might be interested in

Evaluate 82 - 2^3 x5

Anettt [7]

I think the answer is 42.

6 0

3 years ago

Read 2 more answers

Asher is asked to find the factors of 10. His work is below. 10 x 1 10 10 x 2 20 10 x 3 30 So, the factors of 10 are 10, 20, and

kherson [118]

Asher did 10 x 1= 10, 10 x 2= 20, 10 x 3= 30

In Asher's work, each 10 is being multiplied with 1,2,3.

Multiplication represents multiples of a number.

In order to find the factors of a number, we need to find all numbers that can divide that particular number we need to find factor for.

Therefore, to find the factors of 10, we need to find the numbers that can divide 10 completely.

We can start from 1.

10 can be divided by 1. So, first factor of 10 is 1.

Now, if we check 2, we can see that 2 can also divide 10 completely.

Now checking 3,4. Those numbers can't divide 10 completely.

Now checking 5. 5 can also be divide 10 completely.

And next number is 10, that can divide 10 completely.

Therefore, factors of 10 are 1,2,5 and 10.

So, the following statements are applicable:

B) Asher found multiples of 10, not factors of 10.

D) Asher should have gotten this as the answer: 1,2,5, and 10

8 0

3 years ago

Please show me how you were able to get the answer :)

alex41 [277]

$h(x)=\begin{cases}-x^2+4x-3\ \ \forall\ \ x\in [1,3]\\ 0 \ \text{other case} \end{cases}$

8 0

3 years ago

Suppose EG=3, EB=8, A(F)=7, m∠EBG=23, m∠EGF=32, and m∠CAE=51. Find m∠CAF.

ASHA 777 [7]

Answer:

m∠CAF is 28°

Step-by-step explanation:

The given parameters are;

EG = 3, EB = 8, A_F = 7, m∠EBG = 23°, ∠EGF 32°, and m∠CAE = 51°

From the diagram, we have;

m∠EBG = m∠EAD ; ${}$ Given

Therefore, m∠EAD = 23°

m∠CAE = m∠CAF + m∠EAD ${}$ Angle addition postulate

Therefore, we have;

51° = m∠CAF + 23° ${}$

m∠CAF = 51° - 23° ${}$

m∠CAF = 28°

8 0

4 years ago

Gina has 20 groups of 10 pencils 137 are sharpened how many dual pencils does Gina have

saul85 [17]

well, I think the whole group thing is ment to distract you. Math problems can be evil like that. If she has 200 pencils. and 137 ove them a sharp, you have to subtract 137 from 200. 200-137=23 :3 she has 23 unshapened pencils.

7 0

3 years ago