Given : y = 8 - 9x
(a) we need to find value of y when x = 2
substituting x = 2 in y = 8 -9x , we get :
y = 8 - 9(2)
y = 8 - 18
y = -10
(b) we need to find value of y when x = 0
substituting x = 0 in y = 8 -9x , we get :
y = 8 - 9(0)
y = 8 - 0
y = 8
If a logarithm has a coefficient, then the coefficient can also be written as the exponent of the input of the logarithm. In other words, if you have the logarithm alog(x), that is equal to log(x^a). So the expression can be rewritten:
log(x^2)+log(y^3)
If tow logarithms of the same bases are added together that is equal to the logarithm of the product of the inputs of the two original logarithms. In other words, given log(x)+log(y), it can also be written as log(xy). So the expression can be combined into one logarithm:
log(x^2 * y^3)
Its all up to you and how hard you are willing to work to get that may credits in one semester. But you could do it. Hope that helped!
Answer:
D
Step-by-step explanation:
0.36|6=0.366
