All categories

3 years ago

Compare a lunar eclipse and a solar eclipse. For each type of eclipse, be sure to provide evidence that describes:

Biology

1 answer:

Elis [28]3 years ago

6 0

Answer:

A lunar eclipse occurs when the Earth gets in the way of the sun and blocks sunlight from hitting the moon. This makes the moon have a reddish-orange tint to it. A full moon is visible during a lunar eclipse.

A solar eclipse happens when the moon gets in between the sun and the Earth, forming a crown like ring around the moon, which is from the sun. The moon itself might not be visible, due to the angle at which it sun is hitting it at.

You might be interested in

A person with type A blood (AO) is crossed with

riadik2000 [5.3K]

Answer:

25% type A, 25% type B, 25% type AB, 25% type O

If you put it into a punnett square:

B O

A AB AO

O BO OO

you get 25% for each phenotype

7 0

2 years ago

In chickens, comb shape is determined by genes at two loci (R, r and P, p). A walnut comb is produced when at least one dominant

Ivenika [448]

Answer and Explanation:

Available data:

Comb shape is determined by genes at two loci (R, r and P, p).

The walnut comb genotype is R_P_.

The rose comb genotype is R_pp.

The pea comb genotype is rrP_.

The single genotype is rrpp.

a. Walnut crossed with single produces 1 walnut, 1 rose, 1 pea, and 1 single offspring:

Parental) RrPp x rrpp

Gametes) RP Rp rP rp rp rp rp rp

Punnet Square) RP Rp rP rp

rp RrPp Rrpp rrPp rrpp

rp RrPp Rrpp rrPp rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

b. Rose crossed with pea produces 20 walnut offspring.

Parental) RRpp x rrPP

Gametes) Rp Rp Rp Rp rP rP rP rP

Punnet Square) Rp Rp Rp Rp

rP RrPp RrPp RrPp RrPp

F1 phenotype: 100% walnut.

F1 genotype: 16/16 RrPp.

c. Pea crossed with single produces 1 single offspring.

This is not possible, because the pea genotype involves at least one dominant allele P. There are two possible crosses: rrPp x rrpp, which must produce half of the progeny pea and the other half single, or rrPP x rrpp which produce a whole pea progeny with no single offspring.

Parental) rrPp x rrpp

Gametes) rP rp rP rp rp rp rp rp

Punnet Square) rP rp rP rp

rp rrPp rrpp rrPp rrpp

rp rrPp rrpp rrPp rrpp

F1 phenotype: 50% pea, and 50% single.

F1 genotype: 8/16 rrPp, 8/16 rrpp.

d. Rose crossed with pea produces 2 walnut, 1 single, and 1 pea offspring.

This is not possible, because having one of the parents with a rose phenotype involves at least one R allele, which means that there must be rose phenotype in the progeny.

Parental) Rrpp x rrPp

Gametes) Rp Rp rp rp rP rP rp rp

Punnet Square) Rp Rp rp rp

rP RrPp RrPp rrPp rrPp

rP RrPp RrPp rrPp rrPp

rp Rrpp Rrpp rrpp rrpp

rp Rrpp Rrpp rrpp rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

e. Rose crossed with single produces 31 rose offspring.

Parental) RRpp x rrpp

Gametes) Rp Rp Rp Rp rp rp rp rp

Punnet Square) Rp Rp Rp Rp

rp Rrpp Rrpp Rrpp Rrpp

F1 phenotype: 100% rose (31 individuals equal 100% of the progeny).

F1 genotype: 16/16 Rrpp.

f. Rose crossed with single produces 10 rose and 11 single offspring.

Parental) Rrpp x rrpp

Gametes) Rp Rp rp rp rP rP rp rp

Punnet Square) Rp Rp rp rp

rp Rrpp Rrpp rrpp rrpp

F1 phenotype: 50% rose, 50% single.

F1 genotype: 8/16 Rrpp, 8/16 rrpp.

3 0

3 years ago

Mutations in _________ genes lead to transformations in the identity of entire body parts?

Dima020 [189]

Answer:

Homeotic genes

4 0

3 years ago

In all states of matter, atoms of all elements

Pie

A. is your correct answer

3 0

3 years ago

Allen Dexter, a 19-year-old college student, was rock climbing when he fell 30 feet to the ground. Paramedics arriving at the sc

a_sh-v [17]

Answer:

Explanation:

A cervical collar was used to avoid movement and prevent further damage incase he has a fracture.

light is focused in one eye,the pupil will constrict as a respond to the light flashed. It is repeated Again and observed.

The vitals were normal until he had the accident as the patient reached hospital his vitals were abnormal he had achycardia, severe hypotension, increased temperature and shallow breathing which is an indicator of C5 injury. After the surgery and the patient was treated he stabilises and achieved his vitals normal ranges in day 4 of admission.

The X ray result shows he has fracture of the 5th cervical bone.

The blood test shows he has a decreased pH level and an alteration in

his breathing pattern shows he has respiratory acidosis

Cranial tongs was uses to immobilize the neck and prevent it from moving it also aid healing

After the operation it was revealed that he has a damage on both sides of of his 5th Cervical bone which has lead to loss of sensation and strength in his upper arms and lower .It leads to incontinence in urine.

6 0

3 years ago