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tiny-mole [99]
3 years ago
10

Jennifer is organising a street party. she needs to make 300 cakes. the recipe consist of : 50g icing, 150g butter, 120g caster

sugar, 110g flour, 1 egg, 5h baking powder. this makes 12 cakes. how much of each ingredient will she need? kilograms.​
Mathematics
2 answers:
arlik [135]3 years ago
8 0

Answer:

1.25kg icing

3.75kg butter

3kg caster sugar

2.75kg flour

25 eggs

125g baking powder    

Step-by-step explanation:

Above is 6 ingredients that is all part of your answer, but you show 300/12 as your first step in workings , the rest is multiplying by 25 as shown here.

300/12 = 25

25 x 50 = 1250g = 1.25kg

25 x 150 = 3750g = 3.75kg

25 x 120 = 3000g = 3kg

25 x 110 = 2750g = 2.75kg

25 eggs

25 x 5 = 125g

joja [24]3 years ago
4 0

Answer:

1.25 kg of icing sugar

3.75 kg of butter

3 kgs of caster sugar

2.75 kgs flour

25 eggs

125g baking powder

Step-by-step explanation:

300/12 x (weight of ingredient)

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Step-by-step explanation:

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tatyana61 [14]
F=72

g=6

------------

\cos { \left( F \right)  } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }

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\cos { \left( 72 \right)  } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right)  } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }

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But what is e?

E=76

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And:

\frac { e }{ \sin { \left( E \right)  }  } =\frac { g }{ \sin { \left( G \right)  }  }

Which means that:

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If you take this value into account, you will discover that f is...

f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right)  }  }{ \sin { \left( 32 \right)  }  } \left( \frac { 6\cdot \sin { \left( 76 \right)  }  }{ \sin { \left( 32 \right)  }  } -12\cos { \left( 72 \right)  }  \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)

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So, the solution is (x, y) = (-1, -3).

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