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3 years ago

8

I was just wondering this is one of my questions in my math books and i needed help (Its really long i did all the work i just w

anna double check

1 answer:

slava [35]3 years ago

4 0

Answer:

no not that wuch

Step-by-step explanation:

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Please help me asappp! I'll give brainlest and points!

antiseptic1488 [7]

Answer:

1) true

2)true

3)false

4)true

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2 years ago

Read 2 more answers

Yesterday 116 vehicles went through Express Car Wash. Of these vehicles, 74 were minivans. Express the ratio of vehicles other t

riadik2000 [5.3K]

E. 74/116=0.637 hope this helps

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3 years ago

1 each of the two items that Val bought cost more than 10$ 2. Val spent 34$ for the 2 items. 3. Neither of the two items that Va

DerKrebs [107]

Statement : Val spent $ 34 for the 2 items

contradiction : Neither of the 2 items that Val bought cost more then $ 15

think about it....if neither of them cost more then 15....lets say they cost 15 each...then there is no way he spent $ 34.....he would spend at most $ 30

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3 years ago

Read 2 more answers

Multiply or Divide<br><br> (i need this for school tomorrow)

lions [1.4K]

Answer:

Ok so here are the simple rules of doing it (very easy) cause I’m not doing it all so . when multiplying a power with The same base keep the base but add the exponents. Dividing, keep the base (if their the same if not then its already simplified same with multiplication) but SUBTRACT the exponents. Also keep the parenthesis if it’s a negative number base.

I’ll do a few.

11) a^10. 11b) 5^4

12) (-2)^2.

13) 10^2. 13b) s^6

14) -4s^5(t^6) <- [Im not sure of this one)

15) x^3(y^3)

7 0

3 years ago

A television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If

musickatia [10]

Answer:

a. The test statistic for this hypothesis would be z=1.71

b. Critical value at α = 0.10: z=1.282

c. Reject H0, the television network should not keep its current lineup.

d. H0: p ≤ 0.50; HA: p > 0.50

Step-by-step explanation:

We have to performa an hypothesis test on a proportion.

The claim is that the proportion of viewers that prefer the new show is bigger than 50% (meaning that most viewers prefer the new show).

The null hypothesis will state that both shows have the same proportion.

Then, the null and alternative hypothesis are:

$H_0: \pi\leq0.50\\\\H_a: \pi>0.5$

The sample proportion is p=0.53

$p=X/n=438/827=0.53$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.5*0.5}{827}}= 0.017$

Then, the z-statistic can be calculated as:

$z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.53-0.50-0.5/827}{0.017}=\dfrac{ 0.029 }{0.017} =1.706$

The critical value for a right tailed test at a significance level of 0.10 is zc=1.282. This value can be looked up in a standard normal distribution table.

As the statistic is bigger than the critical value, it lies in the rejection region. The null hypothesis is rejected. There is evidence to support the claim that the proportion of viewers which support the new show is larger than 0.50.

4 0

3 years ago