Question

2. The width of a rectangle is 12 inches less than its length. The perimeter of the rect-

Answer 1

Answer:

$P= 2*Lenght + 2*Width$

Since the perimeter is 56 inches we can solve for the lenght with this equation:

$56 in = 2*12in + 2*Length$

And solving for the length we got:

$Length = \frac{56in -24 in}{2} 16 in$

So then the lenght = 16 inhes and the width of 12 inches

Step-by-step explanation:

For a rectangle of width 12 inches and lenght y inches we know that the perimeter is given by:

$P= 2*Lenght + 2*Width$

Since the perimeter is 56 inches we can solve for the lenght with this equation:

$56 in = 2*12in + 2*Length$

And solving for the length we got:

$Length = \frac{56in -24 in}{2} 16 in$

So then the lenght = 16 inhes and the width of 12 inches