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3 years ago

2. The width of a rectangle is 12 inches less than its length. The perimeter of the rect-

Mathematics

1 answer:

Alona [7]3 years ago

5 0

Answer:

$P= 2*Lenght + 2*Width$

Since the perimeter is 56 inches we can solve for the lenght with this equation:

$56 in = 2*12in + 2*Length$

And solving for the length we got:

$Length = \frac{56in -24 in}{2} 16 in$

So then the lenght = 16 inhes and the width of 12 inches

Step-by-step explanation:

For a rectangle of width 12 inches and lenght y inches we know that the perimeter is given by:

$P= 2*Lenght + 2*Width$

Since the perimeter is 56 inches we can solve for the lenght with this equation:

$56 in = 2*12in + 2*Length$

And solving for the length we got:

$Length = \frac{56in -24 in}{2} 16 in$

So then the lenght = 16 inhes and the width of 12 inches

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Step-by-step explanation:

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Statements Reasons

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