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Gnesinka [82]
2 years ago
11

Triangles ABC and DEF are similar. Find the lengths of AB and EF. Right triangles A B C and D E F. Side A B is 5 x, side B C is

4, and hypotenuse A C is unknown. Side D E is 5, E F is x, and hypotenuse D F is blank. a. AB = 2; EF = 10 c. AB = 20; EF = 4 b. AB = 10; EF = 2 d. AB = 4; EF = 20 Please select the best answer from the choices provided
Mathematics
1 answer:
Doss [256]2 years ago
7 0

Answer:

Ummm...

Step-by-step explanation:

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I need help give real answers
finlep [7]

Answer:

B y = -.001x +100

Step-by-step explanation:

(0,100) (2000,98)

98-100/ 2000-0 = -2/2000 = -1/1000

y-100 = -.001(x -0)

y= -.001x +100

7 0
3 years ago
Help assap with this question
Hitman42 [59]
It's the bottom on the right
8 0
3 years ago
At Jefferson Middle School, eighty-two students were asked which sports they plan to participate in for the coming year. Twenty
blondinia [14]

Answer:

30 students they are including the students that are also planning to participate in other sports to.

8 0
3 years ago
A manufacturing process produces integrated circuit chips. Over the long run the fraction of bad chips produced by the process i
Vitek1552 [10]

Answer:

0.0244 (2.44%)

Step-by-step explanation:

defining the event T= the chips passes the tests , then

P(T)= probability that the chip is not defective * probability that it passes the test given that is not defective  + probability that the chip is defective * probability that it passes the test given that is defective = 0.80 * 1 + 0.20 * 0.10 = 0.82

for conditional probability we can use the theorem of Bayes. If we define the event D=the chip was defective , then

P(D/T)=P(D∩T)/P(T) = 0.20 * 0.10/0.82=  0.0244 (2.44%)

where

P(D∩T)=probability that the chip is defective and passes the test

P(D/T)=probability that the chip is defective given that it passes the test

5 0
3 years ago
Hey Guys!
zaharov [31]
<h3>Answer: D)  -3</h3>

Explanation:

Recall that y = f(x) since both are outputs of a function.

If k = 2, then f(x) = 2 leads to y = 2 being a horizontal line drawn through 2 on the y axis. This horizontal line only crosses the cubic curve at one spot. The same can be said if k = 0 and k = -2. So we can rule out choices A,B,C.

On the other hand, if k = -3, then f(x) = -3 has three different solutions. This is because the horizontal line through -3 on the y axis crosses the cubic at 3 different intersection points.

7 0
2 years ago
Read 2 more answers
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