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Gnesinka [82]
3 years ago
11

Triangles ABC and DEF are similar. Find the lengths of AB and EF. Right triangles A B C and D E F. Side A B is 5 x, side B C is

4, and hypotenuse A C is unknown. Side D E is 5, E F is x, and hypotenuse D F is blank. a. AB = 2; EF = 10 c. AB = 20; EF = 4 b. AB = 10; EF = 2 d. AB = 4; EF = 20 Please select the best answer from the choices provided
Mathematics
1 answer:
Doss [256]3 years ago
7 0

Answer:

Ummm...

Step-by-step explanation:

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3 years ago
In a recent contest, the mean score was 210 and the standard deviation was 25. a) Find the z-score of John who scored 190 b) Fin
denpristay [2]

Answer:

a) Z = -0.8

b) Z = 2.4

c) Mary's score was 241.25.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 210, \sigma = 25

a) Find the z-score of John who scored 190

Z = \frac{X - \mu}{\sigma}

Z = \frac{190 - 210}{25}

Z = -0.8

b) Find the z-score of Bill who scored 270

Z = \frac{X - \mu}{\sigma}

Z = \frac{270 - 210}{25}

Z = 2.4

c) If Mary had a score of 1.25, what was Mary’s score?

Z = \frac{X - \mu}{\sigma}

1.25 = \frac{X - 210}{25}

X - 210 = 25*1.25

X = 241.25

Mary's score was 241.25.

3 0
3 years ago
Read 2 more answers
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