Is this correct 1 problem 15 POINTS
2 answers:
First, we should simplify this to see if it is true. The left side is already in simplest form, but the right side isn't. It can be distributed, which is multiplying the numbers inside the parenthesis by two like this: . This equation has many solutions, because both sides both go through the same changes. So you are correct. Nice job. :)
You might be interested in
We need a system of equations to solve this. "Difference" is to subtract, and we are taking this difference of the 2 squared unknowns to be 20. That equation is 
. Our "first number is x^2, so 3 times that is 3x^2. "Increased by" is adding to that first number. What we are adding is the second number. The second equation is 
. Let's solve the first equation for x^2: 
and sub that value for x^2 into the second equation. 
and 
. Subtract 60 from both sides and combine the y^2 terms to get 
. Divide both sides by 4 to get y^2 = 16 and y = 4. Let's go back now and solve for x. We will use the fact that y^2 = 16 to solve for x^2 and then take the square root of it. 
, x^2 = 4, so x = 2. Your solutions are x = 2 and y = 4. There you go!