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3 years ago

What is the square Root of 7 in the nearest 10th... solving the following.

Mathematics

1 answer:

ivann1987 [24]3 years ago

4 0

2.64 i believe if it’s wrong let me know

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Solve for x assume that lines wich appear to be tangent are tangent, please HELPP don't do it just for points please I really ne

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Step-by-step explanation:

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What is the value of k when the expression 3(7 + x) is equivalent 3(x + k)

Free_Kalibri [48]

Answer:7

Step-by-step explanation:

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3 years ago

Solve for P<br><br> P/15=20/25

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p=12

Step-by-step explanation:

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3 years ago

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I NEED HELP QUICK!!!

Tamiku [17]

The equation that shows the correct relationship between the measures of the angles of the two triangles is;

Option D: The measure of angle BCA = The measure of angle C prime A prime B prime

<h3>How to Interpret Objects Transformation?</h3>

We are told that Triangle ABC is transformed to triangle A′B′C′.

Now, the triangle ABC and A'B'C' are similar triangles and we know that similar triangles angles are congruent. Thus;

From the given coordinates, we can say that;

∠BAC = ∠B'A'C'

∠ABC = ∠A'B'C'

∠ACB = ∠A'C'B'

Thus, the equation that shows the correct relationship between the measures of the angles of the two triangles is;

The measure of angle BCA = The measure of angle C prime A prime B prime

Read more about Objects Transformation at; brainly.com/question/2512124

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2 years ago

The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re

PolarNik [594]

Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic clarithromycin is eliminated from the body according to the formula:

$A(t) = 500e^{-0.1386t}$ ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

$100= 500e^{-0.1386t}$

Divide both sides by 500 we get;

$\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}$

Simplify:

$\frac{1}{5} = e^{-0.1386t}$

Taking logarithm both sides with base e, then we have;

$\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})$

$\log_e (\frac{1}{5})=-0.1386t$ [ Using $\log_e e^a =a$ ]

$\log_e (0.2)=-0.1386t$

$-1.6094379124341 = -0.1386t$

[using value of $\log_e (0.2) = -1.6094379124341$ ]

then;

$t = \frac{-1.6094379124341}{-0.1386}$

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams

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3 years ago