Answer:
No, Method is not effective.
Step-by-step explanation:
Let x be the number of girls = 319
and n be the total number of babies = 580
Then, proportion
Standard Error,
The level of significance is:
Confidence Interval:
![p \pm [Z_{\frac{\alpha}{2}} \times SE]\\=0.550 \pm [2.575 \times 0.02066\\=(0.4968, 0.6032)](https://tex.z-dn.net/?f=p%20%5Cpm%20%5BZ_%7B%5Cfrac%7B%5Calpha%7D%7B2%7D%7D%20%5Ctimes%20SE%5D%5C%5C%3D0.550%20%5Cpm%20%5B2.575%20%5Ctimes%200.02066%5C%5C%3D%280.4968%2C%200.6032%29)
Since 0.50 lies in the interval hence we fail to reject
Thus, the method does not appear to be effective.
Answer:
a) independent variable x, dependent variable y
b) independent variable s, dependent variable g
c) independent variable q, dependent variable p
d) independent variable n, dependent variable m
Answer: 75
Step-by-step explanation:
To find the value of 6c-15, we first want to finc the value of c. Once we find c, we can plug it in and solve.
-5c+6=-69 [subtract both sides by 6]
-5c=-75 [divide both sides by -5]
c=15
Now that we have the value of c, we can plug it in and solve.
6(15)-15 [multiply]
90-15 [subtract]
75
The value is 75.
Answer:
the answer is D
Step-by-step explanation:
