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SVEN [57.7K]
3 years ago
7

Witch is not a function {(7,8),(−4,4),(3,8),(−7,−1)} \{(-5, -3), (-1, -8), (-7, 0), (-5, -9)\}{(−5,−3),(−1,−8),(−7,0),(−5,−9)} \

{(8, 4), (6, -1), (-4, 5), (9, 4)\}{(8,4),(6,−1),(−4,5),(9,4)} \{(8, -3), (4, 0), (-4, 9), (3, 2)\}{(8,−3),(4,0),(−4,9),(3,2)}
Mathematics
1 answer:
iris [78.8K]3 years ago
6 0

Given:

The relations are:

{(7,8),(−4,4),(3,8),(−7,−1)}

{(-5, -3), (-1, -8), (-7, 0), (-5, -9)}

{(8,4),(6,−1),(−4,5),(9,4)}

{(8,−3),(4,0),(−4,9),(3,2)}

To find:

The relation that is not a function.

Solution:

A relation is a function if there exist unique y-value for each x-value and a relation is not a function if there exist more than one y-values for any x-value.

In option B, the given relation is:

{(-5, -3), (-1, -8), (-7, 0), (-5, -9)}

Here, y=-3 and y=-9 for x=-5. There exist more than one y-values for x=-5. So, this relation is not a function.

In other three relations, all x-values are different, so there exist unique y-value for each x-value. It means the relations in options A, C and D are functions.

Therefore, the correct option is B.

You might be interested in
Which equation represents a circle with the same center as the circle shown but with a radius of 2 units?
Daniel [21]

Answer:

Option 2: (x-4)^2 + (x-5)^2 = 4

Step-by-step explanation:

The given circle's center is: (4,5)

And the radius is 4 units.

We are told in the question that the center will remain same only the radius will be changed.

The center is denoted by (h,k) = (4,5) and radius is 2

Standard equation of circle is:

(x-h)^2 + (y-k)^2 = r^2

So the equation of another circle with same center and radius of 2 units will be:

(x-4)^2 + (x-5)^2 = 2^2

(x-4)^2 + (x-5)^2 = 4  

Hence option 2 is correct ..

5 0
4 years ago
Could someone help me with this?
hodyreva [135]

Step-by-step explanation:

Identity the variable:

Initial Velocity is 35.

Initial Height is 204

Final Height is 0.

What looking for the time.

So we have

0 =  - 16 {t}^{2}  + (35)t + 204

Use Quadratic Formula,

- b± \frac{ \sqrt{b {}^{2}  - 4ac} }{2a}

A is -16, B is 35 , C is 204.

So we have

- 35± \frac{ \sqrt{ {35}^{2} - 4( - 16)(204) } }{ - 32}

- 35± \frac{ \sqrt{1225 + 2240}  }{ - 32}

- 35± \frac{ \sqrt{3465} }{ - 32}

{35}  ± \frac{ \sqrt{3465} }{ - 32}

The positve solution is

4.83

So the answer is 4.83 seconds

5 0
2 years ago
Help! Pleaseeeeeeeeee
Lunna [17]
Y=x+1
The slope is 1 and the y intersect is 1
3 0
3 years ago
Please solve a, c, d, e, and f i don’t understand this
faust18 [17]

a) n° + n°+ 42 = 180°

2n + 42 = 180

2n = 180 – 42

2n = 138

n = 138 /2

n° = 69°

_____o___o____

b) ( x+10) + x + ( x+5 ) = 180

x + 10 + x + x + 5 =180

3x + 15 =180

3x =180 – 15

3x = 165

x = 165 /3

x° = 55°

_____o___o___

c) 3q + q + q = 180

5q =180

q = 180/5

q=36°

___o___o____

d) m + 2m + ( m+10) = 180

m+2m+m+10=180

4m + 10=180

4m = 180 – 10

4m = 170

m=170 / 4

m = 42.5°

____o___o___

e) y + (y – 30 ) + 90° = 180°

y + y – 30 + 90 = 180

2y + 60 = 180

2y = 180 – 60

2y = 120

y = 120/2

y = 60°

____o___o____

f) ( t + 10.5 ) + 2t + 90 = 180

t + 10.5 + 2t +90=180

3t + 100.5 = 180

3t = 180 – 100.5

3t = 79.5

t = 79.5/3

t =26.5°

I hope I helped you^_^

6 0
3 years ago
Absolute value functions
valkas [14]
I only know one function:
it gives us the exact value of a number
5 0
4 years ago
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