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crimeas [40]
3 years ago
10

Find the volume of the described solid s

Mathematics
1 answer:
Serga [27]3 years ago
8 0

Answer:lol it’s 697

Step-by-step explanation: it could be

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PLEASE HELP! 20 POINTS!!
Ann [662]

Answer:

15

Step-by-step explanation:

In this problem we need to use the numbers given. So in the problem it states that k = 20 and v = 10. We can replace the letters in the equation for the numbers that it equals so the equation can make sense so 25 - 20 + 10 because k is 20 and v is 10 I simply just replaced the letters with the numbers given in the problem. Then we can just subtract 25 - 20 which is 5 and add 10 which leaves you at a final answer of 15. Hope this helped!

3 0
3 years ago
the sum of two numbers is 104. the larger is one less than twice the smaller number. find the numbers
exis [7]

Answer:

The larger number is 69 and the smaller number is 35.

Step-by-step explanation:

Find the equations. Here x will be the larger number and y will be the smaller number.

x + y = 104

x = 2y -1

Substitute:

(2y -1) + y = 104

3y = 105

y = 35

x = 2(35) - 1

x = 70 - 1

x = 69

The larger number is 69 and the smaller number is 35.

8 0
3 years ago
Help Please!!
san4es73 [151]

Answer:

y = -2x + 9

Step-by-step explanation:

y = -2x + 7

(4, 1)

1 = -2 ( 4 ) + b

1 = -8 + b

b = 9

y = -2x + 9

8 0
3 years ago
THIS IS URGENT. A sign at the grocery store says that 3 cucumbers costs $3.60. How much would it cost for 5
Solnce55 [7]

Answer:

18

Step-by-step explanation:

just multiply

8 0
3 years ago
Read 2 more answers
Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.
Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

|AB|=\sqrt{(4--1)^2+(2-2)^2}

\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}

\Rightarrow |AB|=\sqrt{5^2+(0)^2}

\Rightarrow |AB|=\sqrt{25}

\Rightarrow |AB|=5 units.

The length of side BC

|BC|=\sqrt{(3-4)^2+(-1-2)^2}

\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}

\Rightarrow |BC|=\sqrt{1+9}

\Rightarrow |BC|=\sqrt{10}

The length of side AC

|AC|=\sqrt{(3--1)^2+(-1-2)^2}

We simplify to obtain;

|AC|=\sqrt{(3+1)^2+(-3)^2}

\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}

|AC|=\sqrt{16+9}

|AC|=\sqrt{25}

|AC|=5\:units

Since |AC|=5\:units=|AB|, the given triangle is an isosceles triangle.

The correct answer is

6 0
3 years ago
Read 2 more answers
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