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soldier1979 [14.2K]
3 years ago
10

The ________ is the distance from the center to the edge of a circle

Mathematics
2 answers:
iVinArrow [24]3 years ago
8 0

Answer:

Radius

Step-by-step explanation:

yKpoI14uk [10]3 years ago
6 0

Answer:

The answer is radius.

Step-by-step explanation:

Radius is a distance calculated from the center of the circle to the end of the circle.

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In the figure above, AB is tangent to the circle with center O
Radda [10]

<u>Given</u>:

Given that O is the center of the circle.

AB is tangent to the circle.

The measure of ∠AOB is 68° and we know that the tangent meets the circle at 90°

We need to determine the measure of ∠ABO.

<u>Measure of ∠ABO:</u>

The measure of ∠ABO can be determined using the triangle sum property.

Applying the property, we have;

\angle ABO+\angle BAO+\angle AOB=180^{\circ}

Substituting the values, we get;

\angle ABO+90^{\circ}+68^{\circ}=180^{\circ}

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6 0
3 years ago
Please someone answer this please
gladu [14]

Option C:

\frac{3 a^{2} b^{11}}{2 } is equivalent to the given expression.

Solution:

Given expression:

$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}

To find which expression is equivalent to the given expression.

$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}

Using exponent rule: \frac{1}{a^m}=a^{-m}, \ \  \frac{1}{a^{-m}}=a^{m}

    $=\frac{-18 a^{-2} b^{5}a^{4} b^{6}}{-12 }

    $=\frac{-18 a^{-2} a^{4} b^{5} b^{6}}{-12 }

Using exponent rule: {a^m}\cdot{a^n}=a^{m+n}

    $=\frac{-18 a^{(-2+4)} b^{(5+6)}}{-12 }

   $=\frac{-18 a^{2} b^{11}}{-12 }

Divide both numerator and denominator by the common factor –6.

   $=\frac{3 a^{2} b^{11}}{2 }

$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}=\frac{3 a^{2} b^{11}}{2 }

Therefore, \frac{3 a^{2} b^{11}}{2 } is equivalent to the given expression.

Hence Option C is the correct answer.

8 0
3 years ago
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