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ch4aika [34]
3 years ago
13

In the image above, line t is a perpendicular bisector and angle 4 is congruent to angle 6. Write a paragraph to prove that poin

t C is equidistant from points A and B.
Mathematics
1 answer:
Triss [41]3 years ago
5 0
What image sorry cant do it without it
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A mirror is in the shape of an isosceles right triangle and has a hypotenuse length of seven times the square root of two. What
frez [133]

The length of one of the legs  of an isosceles right triangle and has a hypotenuse length of seven times the square root of two is 7 units.

<h3>What is an Isosceles triangle?</h3>

Isosceles triangles are triangles that has two of it sides equal to each other. The base angles of an isosceles triangle are equal.

The  isosceles triangle is also a right angle triangle. The hypotenuse is the longest side of a right angle triangle.

Therefore,

hypotenuse = 7(√2)

let the length of the other legs = x

Therefore, using Pythagoras theorem

c² = a² + b²

(7(√2))² = x² + x²

49 × 2 = 2x²

98 = 2x²

x² = 98 / 2

x = √49

x = 7 units

learn more on isosceles triangle here: brainly.com/question/10412877

4 0
2 years ago
The graph of y=cos (x+ pi/2) is the graph of the y = cos(x) shifted in which direction?
Mama L [17]

Step-by-step explanation

7 0
3 years ago
Read 2 more answers
Free cheat!!!!division!!
In-s [12.5K]

Answer:

3/2      3*5=15

3/2=1.5

Step-by-step explanation:

8 0
3 years ago
Given: x - 5&gt; -2.
Mice21 [21]

Answer: \{x|x \exists \mathbb{R}, x > 3 \}

Step-by-step explanation:

Adding 5 to both sides, we get <u>x > 3.</u>

7 0
2 years ago
The frequency with which a cricket chirps varies directly with the temperature. If the cricket chirps 100 times per minute in 80
Karo-lina-s [1.5K]

The answer is: D) 115

The explanation is shown below:

1. You have that the frequency with which a cricket chirps varies directly with the temperature, which you can express it as following:

y=kx

Where y is the frequency with which a cricket chirps, x is the temperature and k is the constant of proportionality.

2.  If the cricket chirps 100 times per minute in 80° weather, you can calculate k as below:

k=\frac{100}{80}=1.25

3. Therefore, the frequency in 92° weather is:

y=1.25x\\y=(1.25)(92)\\y=115

3 0
3 years ago
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