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2 years ago

This is a continuous set of points in the coordinate plane. It can be, but is not always, straight.

Mathematics

1 answer:

castortr0y [4]2 years ago

5 0

Answer:

Linear. While all linear equations produce straight lines when graphed, not all linear equations produce linear functions. In order to be a linear function, a graph must be both linear (a straight line) and a function (matching each x-value to only one y-value).

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Solve the equation 3x+4y=16 for x

Nadusha1986 [10]

Answer:

3x+4y=16

3x=-4y+16 (Subtract both sides by 4y)

x=-4/3y+16/3 (Divide both sides by 3 to isolate x variable)

4 0

1 year ago

Someone please help

dedylja [7]

Answer:

1. y = -2x + 5

2. y = 3/5x + 5

3. y = -4/5x - 4

4. y = - 1

5. yes

6. yes

7. yes

8. no

Step-by-step explanation:

1. (4,-3) parallel to y= -2x

-3 = -2(4)+b

b=5

2. (-5,2) parallel to y = 3/5x

2= 3/5(-5)+b

b=5

3. (-5,0) -4/5x

0 = -4/5(-5)+b

b = -4

4. (-4,-1)

y= -1

5. yes

6. yes

7. yes

8. no

Same slope = parallel ex. y = -5x +7, y = -5x +12
opposite reciprocal = perpendicular ex. y = -5x +7, y = 1/5x + 12
to find "b" with slope and point

(x,y) y = mx + b

plug in the y value and x value in the eqaution and m=slope, solve for b

7 0

2 years ago

Use implicit differentiation to find an equation of the tangent line to the curve at the given point.

andrew11 [14]

Differentiating both sides of

$x^2 + 2xy - y^2 + x = 20$

with respect to $x$ yields

$2x + 2y + 2x \dfrac{dy}{dx} - 2y \dfrac{dy}{dx} + 1 = 0 \\\\ \implies (2x-2y) \dfrac{dy}{dx} = -1 - 2x - 2y \\\\ \implies \dfrac{dy}{dx} = \dfrac{1 + 2x + 2y}{2(y-x)}$