Answer:
% change in stopping distance = 7.34 %
Step-by-step explanation:
The stooping distance is given by

We will approximate this distance using the relation

dx = 26 - 25 = 1
T' = 2.5 + x
Therefore

This is the stopping distance at x = 25
Put x = 25 in above equation
2.5 × (25) + 0.5×
+ 2.5 + 25 = 402.5 ft
Stopping distance at x = 25
T(25) = 2.5 × (25) + 0.5 × 
T(25) = 375 ft
Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft
% change in stopping distance =
× 100
% change in stopping distance = 7.34 %
<span>(a) Triangles ABC and PQR are similar triangles since they both share 2 congruent angles and therefore their 3rd angle is also congruent. So the triangles are similar due to the AAA similarity theorem.
(b) The area of triangle PQR is 1 million times larger than the area of triangle ABC. This can be shown since the area of a triangle is 1/2 base times height. You can show that the base of triangle PQR is 1000 times larger than the base of triangle ABC. And since all the sides are in proportion to each other, the height of triangle PQR is also 1000 times larger than the height of triangle ABC. And since 1000 times 1000 equals 1,000,000 or 1 million, the area of triangle PQR is 1 million times larger than triangle ABC.</span>
Answer:
2:3
Step-by-step explanation:
4:6
4/2=2
6/2=3
Answer:
multiply by 12 and would serve 18 people
Step-by-step explanation:
I did a test for it
Answer:
Inez worked for 2 hours 32 minutes more than Joe
Step-by-step explanation:
Here, we are to calculate the difference in the amount of time in which both of them spent working.
Mathematically, that would be the time spent by Inez minus the time spent by Joe
= 7 hrs 23 minutes - 4 hrs 51 minutes
This works like normal arithmetic subtraction;
Since we cannot subtract 51 minutes from 23 minutes, we need to borrow 1 hour ( 60 minutes) from 7 , and it becomes 6 while our minutes become (60 + 23 = 83 minutes).
So the difference here will be (6-4)hrs and (83-51) minutes = 2 hrs 32 minutes