Answer:
1/14
Step-by-step explanation:
P(red, then black) =
·
=
=
(simplifed form)
Answer:
A. 0.2
Step-by-step explanation:
First make the table.
<u>10-grade</u> <u>11-grade</u> <u>12-grade</u> <u>Total</u>
<u>Woodson high school </u> | 110 | 120 | 80 | 310 |
<u>Valley high school </u> | 180 | 150 | 120 | 450 |
<u>Riverside high school </u> | 160 | 140 | 200 | 500 |
<u>Total </u> | 450 | 410 | 400 | 1260 |
Question: In decimal form, to the nearest tenth, what is the probability that a randomly selected riverside high school student is in twelfth grade?
First, find 12-grade and riverside high school number. 200. Take the total lined up with total number, which is 1260, and divide 200 divided by 1260.
200/1260=0.2
The answer is 0.2.
Hope this helps!
If not, I am sorry.
9514 1404 393
Answer:
- 12 boxes
- 10 pencils, 9 notebooks
Step-by-step explanation:
a) The number of boxes will be the greatest common divisor (GCD) of the numbers 120 and 108. That number is 12.
120 = 12×10
108 = 12×9 . . . . 12 is the greatest common divisor
Matthew can make 12 boxes with equal numbers of the items.
__
b) 120 pencils divided by 12 will be 10 pencils per box.
108 notebooks divided by 12 will be 9 notebooks per box.
_____
<em>Additional comment</em>
It helps to be familiar with multiplication tables up to about 12×12.
The GCD can always be found using Euclid's algorithm. Look at the remainder when the larger number is divided by the smaller. If it is not zero, then replace the larger number with the remainder and repeat. If the remainder is zero, the divisor is the GCD.
Here, we have ...
120/108 = 1 r 12.
108/12 = 9 r 0 ⇒ 12 is the GCD
Answer:
D) 5.6, 6, 6, 1
Step-by-step explanation:
Before we start solving this problem, we need to first rearrange the provided data from smallest to greatest, so we get:
5, 5, 5, 5, 6, 6, 6, 6, 6
now we can find the mean. The mean is nothing but the average of the provided values, so we need to add them and then divide them into the total amount of data:

next, in an odd number of data, the median is the middle number when written in order. In this case the middle number (the one in the position 5) is 6, so:
median=6
the mode will tell you what is the value that has the greatest number of occurrencies. This is the number that appears the most on our list.
Mode=6
and the range is the difference between the greatest value and the smallest value:
Range=6-5=1
so the answer is D.
Check the picture below, so the circle looks more or less like so, with a radius of 9.
![\textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=9 \end{cases}\implies C=2\pi (9)\implies C\approx 57](https://tex.z-dn.net/?f=%5Ctextit%7Bcircumference%20of%20a%20circle%7D%5C%5C%5C%5C%20C%3D2%5Cpi%20r~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D9%20%5Cend%7Bcases%7D%5Cimplies%20C%3D2%5Cpi%20%289%29%5Cimplies%20C%5Capprox%2057)