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pav-90 [236]
3 years ago
15

A researcher conducts an independent-measures study examining the effectiveness of a group exercise program at an assisted livin

g facility for elderly adults. One group of residents is selected to participate in the program, and a second group serves as a control. After 6 weeks, the researcher records a combined score measuring balance and strength for each individual. The data are as follows:
Control Exercise n = 10 n = 15 M = 12 M = 15.5 SS = 120.5 SS = 190.0
a. Does the exercise program have a significant effect? Use an alpha level of .05, two tails.

b. Compute Cohen�s d to measure the size of the treatment effect.

Mathematics
1 answer:
Veronika [31]3 years ago
4 0

Answer:

Check the explanation

Step-by-step explanation:

Kindly check the attached images below to see the step by step explanation to the question above.

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An electric current of 0.25 A passes through a circuit that has a resistance of
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37.5 V

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3 years ago
What is the product of (3a + 2)(4a? - 2a + 9)?
yan [13]

Answer:

The answer is 12a^3+2a²+23a+18 ....

Step-by-step explanation:

The given terms are:

(3a + 2)(4a² - 2a + 9)

Now multiply each value of second bracket with the first bracket:

=4a²(3a+2) -2a(3a+2)+9(3a+2)

=12a^3+8a²-6a²-4a+27a+18

Solve the like terms:

=12a^3+2a²+23a+18

Therefore the answer is 12a^3+2a²+23a+18 ....

4 0
3 years ago
In which direction does the right side of this graph point? F(x)= -x^4-x^3+4x-2
suter [353]

Answer: Down

Step-by-step explanation:

We know that the graph of  y = x 4  has both arms pointing up.

Now, since the leading coefficient of  f ( x )  is negative, both arms are pointing down. Thus the right side is pointing down.

4 0
2 years ago
Select the correct answer.
irinina [24]

Answer:

A tax is a compulsory financial charge or some other type of levy imposed on a taxpayer by a governmental organization in order to fund government spending ...

6 0
3 years ago
Read 2 more answers
Please solve this sheet.
lyudmila [28]
Hello,

A: roots: -1,-3
a point (-2,1)
Vertex=((-2,1)

y=k*(x+1)(x+3) using roots
but k*(-2+1)(-2+3)=1==>k*(-1)*1=1==>k=-1

eq: y=-(x+1)(x+3)
==>y=-(x²+3x+x+3)
==>y=-x²-4x-3
y=k(x+2)²+1 if x=-1,y=0 ==>k*1+1=0==>k=-1
==>y=-(x+2)²+1

Answer :A--> R,K

B)
y=k(x+4)²-2 and k=-1/2
y=-1/2(x+4)²-2
y=-1/2x²-4x-10

answer B--> I,≈W if it is written -1/2*x²  (square has been forgotten)

C:
y=2x²-16x+30
y=2(x-4)²-2
answer : C-->S,J

D:
y=-(x+3)(x+1)
y=-x²-4x-3
=-(x+2)²+1
answer D--> V,L

E:
Here there is a problem: or the graph is wrong, or 2 equations are missing!

y=1(x+1)(x-3) using roots
y=x²-2x-3 ≈ T si it were -2x and not +2x.

y=(x-1)²-4 ≈H is it were -1 in place of +1 [H:y=(x+1)²-4]




6 0
3 years ago
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