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3 years ago

Need answer ASAP please :/

Mathematics

1 answer:

Setler [38]3 years ago

7 0

Step-by-step explanation:

Im going to guess (A.) please tell me if im right and r u doing edgenuty same

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ariana's 150g bag of trail mix is x% raisins. brandon's 250g bag of trail mix is y% raisins. they combine the two mixes together

Tema [17]

Answer:

(3x+5y)/8

Step-by-step explanation:

The total amount is 150+250=400

We then do (3x+5y)/2 × 1/400

This equals (3x+5y)/800

We multiply that by 100 giving us the final answer.

7 0

2 years ago

a baby blue whale weighed 5200 lbs birth. after 2 days the baby weighed 5710. after 14 days the baby weighed 8180 lbs is it prop

sveticcg [70]

Answer:

NOPE

Step-by-step explanation:

6 0

3 years ago

I need help with #39-42, please explain.

shusha [124]

For question 39 & 40, we need to use the below equation to complete the sentence

$l=m\sqrt{n}$

Question 39:

When ' n ' increase, the $\sqrt{n}$ will also increase and that multiplied with constant ' m ', the l will also increase.

Solution for question 39:

As $n$ increases and $m$ stays constant , $l$ increases

-------

Question 40:

Solving the equation for m, we get

$l = m\sqrt{n} \\ \\ m=\frac{l}{\sqrt{n}}$

When ' l ' increases, the numerator increase, the denominator stays constant because 'n' stays constant, for this condition, the fraction increases.

Solution for question 40:

As $l$ increase and $n$ stays constant, $m$ increases

------

For question 41 & 42, we need to use the below equation to complete the sentence

$r=s^2/t^2$

Question 41:

When $s$ is triped, the equation will be...

$r=(3s)^2/t^2=\frac{3^{2}s^{2}}{t^2} =9s^2/t^2$

Solution for question 41:

If $s$ is tripled and $t$ stays constant, $r$ is multiplied by 9

--------

Question 42:

When t is doubled, the equation will be...

$r=s^2/(2t)^2=\frac{s^2}{2^2 \cdot t^2}=\frac{s^2}{4t^2}\\ \\ r=0.25s^2/t^2 \; \; (or) \; \; \frac{1}{4} \cdot \frac{s^2}{t^2}$

Solution for 42:

If $t$ doubled and $s$ stays constant, $r$ is multiplied by 1/4 or 0.25

3 0

3 years ago

A(n - 3) +8= bn for n please help me

Papessa [141]

Given equation: A(n - 3) +8= bn.

Solution: On the left side of the equation we have A(n-3).

We don't have any sign in between A and parenthesis (n-3).

So, we need to multiply A and (n-3).

We need to apply distributive property to multiply A and (n-3).

Distributing A over (n-3), we get

A(n-3) = A*n - 3*A = An -3A.

Substituting this value in original equation,

An -3A +8= bn.

We need to solve it for n, so we get n terms on a side.

We have An on left side, we need to get rid n from left side.

Subtracting An from both sides, we get

An -3A +8-An= bn-An.

-3A +8 = bn - An.

We can see n is a common factor on rigth side in bn-an.

Factoring out n on right side from bn-an.

-3A +8 = (b - A)n.

Dividing both sides by (b-A),

$\frac{(-3A+8)}{(b-A)} = \frac{(b-A)n}{(b-A)}$

On right (b-A) paranthiss cancelled and we get n on right side.

$\frac{(-3A+8)}{(b-A)} =n$ Final answer.

So, that would be our final answer

n = (-3A+8)/(b-A)

7 0

3 years ago

Can someone please help me with this?

viktelen [127]

Answer:

Step-by-step explanation:

hopes this helps i have a F in math so not sure

6 0

2 years ago