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Ber [7]
3 years ago
8

Find the volume of a sphere with a diameter of 25 cm. Approximate pi as 3.14 and round your answer to the nearest hundredth.

Mathematics
1 answer:
Sholpan [36]3 years ago
7 0

Answer: The volume of the sphere is 8177.08

Step-by-step explanation:

v= 4/3nr^3

v= 4/3*3.14*1953.125

v= 8177.08

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Do natural numbers have multiplicative inverse
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No,because a multiplcative inverse is when your changing a division or multiplcation sign!
6 0
3 years ago
Please help. Will select brainliest.
IrinaK [193]

Answer:

Heptagon: D

Spetagon: D

Nonagon: B

7 0
3 years ago
From midnight to 2:00 am, the temperature rose 1.15°C each hour. If the temperature at 2:00 am was -2.7°C, what was the temperat
malfutka [58]

Answer: -5 degrees Celsius

Step-by-step explanation:

Temp at 2:00am = -2.7

2:00am is two hours after midnight

During that time the temperature has risen by 1.15 degrees every hour so has risen in total by:

1.15x2 = 2.3 degrees

-2.7-2.3=-5

It was -5 degrees at midnight

3 0
2 years ago
The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes
saul85 [17]

Answer:

a)0.08  , b)0.4  , C) i)0.84  , ii)0.56

Step-by-step explanation:

Given data

P(A) =  professor arrives on time

P(A) = 0.8

P(B) =  Student aarive on time

P(B) = 0.6

According to the question A & B are Independent  

P(A∩B) = P(A) . P(B)

Therefore  

{A}' & {B}' is also independent

{A}' = 1-0.8 = 0.2

{B}' = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B')  (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

P(\frac{B'}{A}) = \frac{P(B'\cap A)}{P(A)} = \frac{0.4\times 0.8}{0.8} = 0.4

Part c)

Assume the events are not independent

Given Data

P(\frac{{A}'}{{B}'}) = 0.4

=\frac{P({A}'\cap {B}')}{P({B}')} = 0.4

P({A}'\cap {B}') = 0.4 x P({B}')

= 0.4 x 0.4 = 0.16

P({A}'\cap {B}') = 0.16

i)

The probability that at least one of them is on time

P(A\cup B) = 1- P({A}'\cap {B}')  

=  1 - 0.16 = 0.84

ii)The probability that they are both on time

P(A\cap  B) = 1 - P({A}'\cup {B}') = 1 - [P({A}')+P({B}') - P({A}'\cap {B}')]

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0
3 years ago
Dwayne starts at the surface of the water and swims to -25 feet. From there he swims +10 feet to see the fish and then back down
d1i1m1o1n [39]
(-25) + 10 + (-5) = -20 feet is his current position. To reach zero, he should add 20 feet to his altitude.
7 0
3 years ago
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