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sladkih [1.3K]
3 years ago
9

Gina deposited her $1,200 stimulus check into an account yielding 3.4% interest compounded monthly. How much money should be in

the account after 10 years?
A. 1435.67


B. 1685.13


C. 1202.34
Mathematics
1 answer:
Tasya [4]3 years ago
3 0

The answer is B The final balance is $1685.13

Step-by-step explanation:

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Thank you for posting your question here at brainly. It 35 degrees if there are <span>are two regular twelve-sided shapes, also known as dodecagons. Dodecagon is a figure with 12 sides. I hope the answer helps. Please don't hesitate to post if you have other questions. </span>
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Plz help! ASAP!  What is −15÷35 ? −25 −9 −19 −125
nasty-shy [4]
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3 years ago
Read 2 more answers
2y - 7+ 5y = 0<br> Step by step work
Ugo [173]

Answer:

y=1

Step-by-step explanation:

2y+5y-7=0

Combine y: 7y-7=0

Move 7 over: 7y=7

Divide by 7:y=1

5 0
4 years ago
Write the expression using the fewest number of bases possible.<br><br>5^3 x 25
rodikova [14]

Answer:

The answer to your question is: 5⁵

Step-by-step explanation

                                                  5³ x 25

First, find the prime factors of 25

             25   5

               5    5

                1                     so, 25 = 5 x 5  or 5²

                      5³ x 5²        Remeber that final power is the sum of the powers

                         5⁵                Finally

3 0
3 years ago
Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}
Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

f(A) = \{x^2  \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2  \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4]  = f(A \cap B)\\

Therefore it is true for intersection. Now for union, we have that

A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]

Therefore, for this case, it would be true that f(A\cup B) = f(A)\cup f(B).

(b)

1 is not a set.

(c)

To begin with  

A\cap B \subset A,B

Therefore

g(A\cap B) \subset g(A) \cap g(B)

Now, given an element of g(A) \cap g(B) it will belong to both sets, therefore it also belongs to g(A\cap B), and you would have that

g(A)\cap g(B) \subset  g(A \cap B), therefore  g(A)\cap g(B)  =  g(A \cap B).

(d)

To begin with A,B  \subset A \cup B, therefore

g(A) \cup g(b) \subset g(A\cup B)

7 0
4 years ago
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