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Vanyuwa [196]
3 years ago
11

Asked what the central limit theorem says, a student replies, "As you take larger and larger samples from a population, the hist

ogram of the sample values looks more and more Normal."Is the student right? Explain your answer.a.No. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means.b.No. As you take larger and larger samples, the histogram of the sample values looks less Normal.c.Yes. This is exactly what the theorem says.Yes, as long as the population distribution is Normal.
Mathematics
1 answer:
Elena L [17]3 years ago
3 0

Answer:

a.No. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means

Step-by-step explanation:

If the sample size is large, means follow a normal distribution even if the data is not normal

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Please help and thank you
ICE Princess25 [194]

Answer:

30

Step-by-step explanation:

15/3=5

5 x 5 = 25

25 + 5 = 30

4 0
3 years ago
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Anybody know how to solve this?
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The answer would be A. I just did this yesterday. Do you want the steps?

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3 years ago
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a circle with radious of 1cm sits inside a 11cm times 12 cm rectangle what is the area of the shaded region
Nitella [24]

Answer: 128.86cm²

Step-by-step explanation:

The circle is inscribed in the rectangle. To find the shaded portion, subtract he area of the circle from the are of the rectangle.

Area of the rectangle                                  =  11 x 12

                                                                     =  132cm²

Area of the circle with radius of 1cm          =  πr²

                                                                     = 3.142 x 1²

                                                                     = 3.142cm²

Therefore , area of the shaded  region      = 132cm²  -  3.142cm²

                                                                    = 128.86cm²

7 0
3 years ago
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Pythagoras help needed please
boyakko [2]

Answer:

See explanation

Step-by-step explanation:

Find the diagonal of the square. The side of the square is 5 cm long. By the Pythagorean theorem,

\text{Diagonal}^2=\text{Side}^2+\text{Side}^2\\ \\\text{Diagonal}^2=5^2+5^2\\ \\\text{Diagonal}^2=25+25\\ \\\text{Diagonal}^2=50\\ \\\text{Diagonal}=\sqrt{50}=5\sqrt{2}\approx 7.07\ cm

If the square (being inside the circle) touches the circle, then the diagonal of the square is exactly the diameter of the circle. The diameter of the circle is twice the radius of the circle, so

\text{Diameter}=2\times 5=10\ cm

Since the diagonal is shorter than the diameter, the square can fit into the circle without touching the circle.

6 0
4 years ago
When reading a book, Charlie made a list by writing down the page number of the last page he finished reading at the end of each
Assoli18 [71]

Answer:

No. of pages he read by the end of the 8th day = 425

Step-by-step explanation:

Charlie started from page 1 and read the same number of pages each day. Suppose x is the number of pages he read each day, the last page he read on the first day would be:

<u>Last page for day 1 = 1 + x</u>

This would be the first number he noted on the list.

The second page number can be determined by adding the number of pages he read to the last page for day 1.

Last page for day 2 = 1 + x + x

                                 = 1 + 2x

Similarly, the last page he read on the third day is:

Last page for day 3 = 1 + 3x. Similarly,

Last page for day 4 = 1 + 4x

Last page for day 5 = 1 + 5x

Last page for day 6 = 1 + 6x

Last page for day 7 = 1 + 7x

Last page for day 8 = 1 + 8x

His Mom added all of the page numbers and got a total of 432. So,

432 = 1+x + 1+2x + 1+3x + 1+4x + 1+5x + 1+6x + 1+7x + 1+8x

432 = 8 + 8x

8x = 432-8

8x = 424

x = 424/8

x = 53

By the end of the 8th day he actually read 1 + 8x pages. Substituting the value of x in this expression, we get:

No. of pages he read by the end of the 8th day = 1 + 8(53)

                                                                               = 1 + 424

No. of pages he read by the end of the 8th day = 425

4 0
4 years ago
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