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Sunny_sXe [5.5K]
3 years ago
6

Help asap plz, dhdhhshdhdhd

Mathematics
1 answer:
IgorLugansk [536]3 years ago
7 0

Answer:

x=7

Step-by-step explanation:

The two marked angles in the image are supplementary, so we can form the following equation:

2x-3=x+4

We can solve that equation to find <em>x</em>.

2x-3=x+4

2x=x+7

x=7

<u><em>I hope this helps.</em></u>

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Which of the following completes the rule for this translation, (x, y) → (x − 8, ___)?
almond37 [142]

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The answer would be c

Step-by-step explanation:

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3 years ago
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Factor out the GCF of the expression:
Leni [432]

Answer:

The GCF of 25 and 35 is 5.

Explanation:

One way to find the GCF is to find the prime factorization of each number. So,

25=52

35=5⋅7

Now, we can find all the factors 25 and 35 have in common. We see that 25 and 35 both have a 5, but not 52 because 35 only has one 5.

35 also has a 7, but that is not in the prime factorization of 25, so we do not include it. Since there is only one common factor which is 5, that is our "greatest common factor

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3 years ago
What is this answer equal to
DerKrebs [107]
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8 0
4 years ago
Can someone please help me solve this ? (x^?) = x6.
PolarNik [594]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Two mechanics Worked on a car The first mechanic charge $55 per hour The second mechanic charge $80 per hour the mechanics work
Tems11 [23]

a = hours worked by the first mechanic

b = hours worked by the second mechanic.

since the first mechanic charges $55 per hour, then for "a" hours that'd be a total of 55*a or 55a, likewise, for the second mechanic that'd be a total charge of 80*b or 80b.

we know all hours combined are 15, so then a + b = 15.

we also know that all charges combined are $950, so 55a + 80b = 950.

\bf \begin{cases} a+b=15\\ \boxed{b}=15-a\\ \cline{1-1} 55a+80b=950 \end{cases}\qquad \qquad \stackrel{\textit{substituting on the 2nd equation}}{55a+80\left( \boxed{15-a} \right)=950} \\\\\\ 55a+1200-80a=950\implies -25a+1200=950\implies -25a=-250 \\\\\\ a=\cfrac{-250}{-25}\implies \blacktriangleright a = 10\blacktriangleleft \\\\\\ \stackrel{\textit{since we know that}}{b=15-a\implies }b=15-10\implies \blacktriangleright b=5 \blacktriangleleft

5 0
3 years ago
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