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Pie
3 years ago
14

Find the perimeter of the shape below:

Mathematics
2 answers:
Alexandra [31]3 years ago
7 0

Answer:

21.4

Step-by-step explanation:

PSYCHO15rus [73]3 years ago
4 0

The given points are:

A             -4            3

B             0              2

C             2              4

D             0              -3

 

We use the distance formula to calculate for the length of each segment.

D^2 = (x2 – x1)^2 + (y2 – y1)^2

 

For segment AB:

D^2 = (0 + 4)^2 + (2 – 3)^2 = 17

D = sqrt 17

 

For segment BC:

D^2 = (2 - 0)^2 + (4 - 2)^2 = 8

D = sqrt 8

 

For segment CD:

D^2 = (0 - 2)^2 + (-3 – 4)^2 = 53

D = sqrt 53

 

For segment DA:

D^2 = (-4 - 0)^2 + (3 + 3)^2 = 52

D = sqrt 52

 

Getting the sum of all the segments will give the perimeter.

Perimeter = sqrt 17 + sqrt 8 + sqrt 53 + sqrt 52

Perimeter = 21.44

 

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Answer:

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3 years ago
Explain how you got the answer
Gnoma [55]

Answer:

\huge\boxed{Center = (3,3),Radius = 2\sqrt{15} }

Step-by-step explanation:

<u><em>Given equation is</em></u>

x^2 + y^2 -6x-6y -42 = 0

Adding 42 to both sides

x^2 + y^2 -6x-6y = 42\\

Completing squares

x^2 -6x+y^2 -6x = 42\\(x)^2 - 2(x)(3) +y^2 - 2(y)(3) = 42

Adding (3)² => 9 and (3)² => 9 to both sides

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We get:

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7 0
3 years ago
Help!!! Which one no need to explain!
azamat

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5 0
3 years ago
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Answer:

Ok soo.

Step-by-step explanation:

sum of two adjacent angles of parallelogram is 180

so angle K + angle L = 180

as AK bisects angle K and LA bisects angle L

so, angle AKL + angle ALK = 180 /2 = 90

in triangle AKL,

angle AKL + angle ALK+angle KAL = 180(sum of all angles in triangle = 180)

so, from above two equations,

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4 0
3 years ago
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The numerator and denominator can be divided by 4 to get 12/25.

48 / 4 = 12
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3 years ago
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