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Ivenika [448]
3 years ago
12

Simplify the given expression. Cite a property from Theorem 6.2.2 for each step. (A − (A ∩ B)) ∩ (B − (A ∩ B)) Let A and B be an

y sets. Then (A − (A ∩ B)) ∩ (B − (A ∩ B)) = = (A ∩ (A ∩ B)c) ∩ (B ∩ (A ∩ B)c) = A ∩ ((A ∩ B)c ∩ (B ∩ (A ∩ B)c)) = A ∩ (((A ∩ B)c ∩ B) ∩ (A ∩ B)c) = A ∩ ((B ∩ (A ∩ B)c) ∩ (A ∩ B)c) = A ∩ (B ∩ ((A ∩ B)c ∩ (A ∩ B)c)) = A ∩ (B ∩ (A ∩ B)c) = (A ∩ B) ∩ (A ∩ B)c = ∅
Mathematics
2 answers:
Alenkinab [10]3 years ago
6 0

Answer:

Step-by-step explanation:

Consider the sets A and B

(A − (A ∩ B)) ∩ (B − (A ∩ B))

= (A ∩ (A ∩ B)c) ∩ (B ∩ (A ∩ B)c) by the set difference law

= (A ∩ (Ac ∩ B)c) ∩ (B ∩ (Ac ∩ B)c) by De Morgan's law

= {(A ∩ Ac) ∪ (A ∩ Bc)} ∩ {(B ∩ Ac) ∪ (B ∩ Bc)} by the distributive law

= {∅ ∪ (A ∩ Bc)} ∩ {(B ∩ Ac) ∪ ∅} by complementation

= {A ∩ Bc} ∩ {B ∩ Ac} by identity law

= (A ∩ Ac) ∩ (B ∩ Ac) by the associative law

= ∅ ∩ ∅ by complementation

= ∅ by the universal bound law

Therefore,  (A − (A ∩ B)) ∩ (B − (A ∩ B)) = ∅

Rus_ich [418]3 years ago
3 0

Answer:

BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH BRUH

Step-by-step explanation:

my cat came and told me in my bath with my toaster listening to despacito by drake my mom and dad also wanted to box me for sum v-bucks

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