Well she charged twice as much to walk large then small. Let s be small and l be large.
We we know that
l = 2s
we also know that she wants to make 100 so
xl + ys = 100
Where where x is number of large and y is number of small. it says she walked 10 small and 5 large so
5l + 10s = 100
substitute 2s for l because they are same value as shown in first equation I made
5 (2s) + 10s = 100
10s + 10s = 100
20s = 100
s = 5
we can now solve for l
l = 2s
l = 2 * 5
l = 10
So s is 5 and l is 10.
3(1)^2-3= 0
Plug in the numbers because x=1 plug In 3(1)^2 and it equals 3 then subtract y which is 3-3= 0
Forty two plus sixty three that's your answer
I am assuming this is a triangle.....P = a + b + c
P = 2a - 3 + 2a + 3a + 1....combine like terms
P = 7a - 2 <==
(-4,-5)(-4,6)(3,8)
all y signs become opposite!:)
