Answer:
r>6
Step-by-step explanation:
5(6+3r) +7>127
30+15r+7>127
37+15r>127
15r>127-37
15r>90
r=6
To make this a little clearer, let's give the pairs of inequalities the same denominator:
<span>Question 1:
</span>

?

First, apply the common denominator to the first fraction:

Do the same for the second:

Nest, compare the two fractions:

Therefore:

>

<span>
Question Two:</span>

?

Apply the common denominator to fraction one:

Fraction two:

Evaluate:

>

Therefore:
<span>
> 
</span>
Hope this helps!
Answer:
Using distribute property
0.5(8a)(a) + 0.5(6b)(a) + 4b
4a^2 + 3ab + 4b
Step-by-step explanation:
Step-by-step explanation:
12 = 2 × 2 × 3
18 = 2 × 3 × 3
56 = 2 ×2 × 2 × 7
Now
Common factor = 2
Remaining factor = 2 × 3 × 2 × 3 × 7
LCM = RF × CF
= 504
hence the lCM of 12 , 18 and 56 is 504...
