Answer: b. 134
Step-by-step explanation:
Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.
Let x denotes a usual value.
i.e. 135.8< x < 155.9
Therefore , the interval for the usual values is [135.8, 155.9] .
If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.
Let's check all options
a. 137 ,
since 135.8< 137 < 155.9
So , it is usual.
b. 134
since 134<135.8 (Minimum value)
So , it is unusual.
c. 146
since 135.8< 146 < 155.9
So , it is usual.
d. 155
since 135.8< 1155 < 155.9
So , it is usual.
Hence, the correct answer is b. 134 .
The answer is 12.8 cm³
<span>The volume ( v) of a gas in a container at a constant temperature varies inversely as the pressure (p):
v = k/p
p * v = k (k - constant)
p1v1 = k
p2v2 = k
So, p1v1 = p2v2
v1 = 24 cm</span>³
p1 = 16 lb
v2 = ?
p2 = 30 lb
24 * 16 = x * 30
384 = x * 30
x = 384 / 30
x = 12.8 cm³
Diameter so i’m assuming it’s one :)
2x^2=-26
x^2=-13
x=(+/-)sqrt(13)i
