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posledela
3 years ago
13

2. Solve the system using substitution. (1 point)

Mathematics
2 answers:
AveGali [126]3 years ago
7 0

Answer:

(8, 11 )

Step-by-step explanation:

Given the 2 equations

2x + 2y = 38 → (1)

y = x + 3 → (2)

Substitute y = x + 3 into (1)

2x + 2(x + 3) = 38 ← distribute and simplify left side

2x + 2x + 6 = 38

4x + 6 = 38 ( subtract 6 from both sides )

4x = 32 ( divide both sides by 4 )

x = 8

Substitute x = 8 into (2) for corresponding value of y

y = 8 + 3 = 11

Solution is (8, 11 )

Pepsi [2]3 years ago
7 0
It’s (8,11) if you sub everything
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Its 8/10 or 12/15 because 4 times 2 is 8 and 5 times 2 is ten
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3 years ago
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If y=6 when x=15 then which of thr following is the value of x when y=20
denis23 [38]

Answer:

if you meant x times y...

15 x 20 is 300.

if you meant x + y...

15 + 20 is 35.

if you meant anything else, please let me know

the way it was written confused me but I tried.

7 0
3 years ago
Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.
gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant  is  mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is  mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)

The partial derivatives of a function are f x and f y.

\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\

&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}

In conclusion,  the area is

A=3 √4 units ^2

Read more about the plane

brainly.com/question/1962726

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5 0
1 year ago
PLSSS HELPPPPP!!!! Evaluate the expression. -1 - (-6 + 10) = -1 =​
Pie

Answer:

3

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6 0
3 years ago
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6. The ABC Book Club charges a $40 monthly fee, plus $2 per book read in that month. The Easy Book Club charges a $35 monthly fe
d1i1m1o1n [39]

The expression for the cost of the ABC Book Club is 2<em>x </em>+ 40.  The expression for the cost of the Easy Book Club is 3<em>x</em> + 35.  To find when the total charge for both book clubs is equal, the two expressions must equal each other. (<em>x </em>= the number of books read)

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Subtract 35 from both sides.

2<em>x </em>+ 5 = 3x

Subtract 2<em>x </em>from both sides.

5 = <em>x</em>

So, the total charge for each club is equal when 5 books are read.

5 0
3 years ago
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