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lesantik [10]
2 years ago
6

What is f(x)=2(3)^x?

Mathematics
1 answer:
HACTEHA [7]2 years ago
4 0

Answer:

This is an exponential function

Step-by-step explanation:

f(x)=2(3)^x is one example of the exponential function.  Since f(0) = 2(1) = 2, the y-intercept is (0, 2).  The x-axis is the horizontal asymptote.  The graph begins in Quadrant II, passes through (0, 2) and continues to increase, faster and faster, in Quadrant I.  Next time, please be more specific about what you'd like to know.

You might be interested in
|x|+5=18 <br> 5 or - 5 <br> 13 or - 13 <br> 18 or - 18 <br> 23 or - 23
slava [35]
Just transpose the 5 to the right side of 18 so it will look like this, /x/ = 18 - 5
Then get the difference and it would be 13. So to check this out if it is correct, substitute x for the value of 13 and it will look like this.
13 + 5 = 18
I hope my answer helped you.
6 0
3 years ago
The United States Government used to make coins of many different values. For each coin, states its worth as a percentage of $1.
STatiana [176]

Answer:

Step-by-step explanation:

Given the following coin values ;

A) 1/2 B. 3 cents C. 20 cents D. $2 1/2 E. $5, state it's worth as a percentage of $1

A) $1/2 as a percentage of $1

$1/2 = $0.5

($0.5/ $1) × 100% = 50%

B) 3 cent as a percentage of $1

3 cent = 3/100 = $0.03

($0.03/$1) × 100% = 3%

3 0
3 years ago
What is an algebraic expression for a number n divided by 4
Morgarella [4.7K]

n/4 because all it wants is a number which is expressed by n divided by 4



8 0
3 years ago
Which of the following is the solution to 4|x+2|&gt;=16. HELP ME RIGHT NOW
m_a_m_a [10]

Answer:

yes

Step-by-step explanation:

4 0
3 years ago
The sum of the first term of an ap is 240 and the sum of the next 4 term is 220 find the first term of the ap
Sindrei [870]

Answer:

The common difference is -5/4

T(n) = T(0)  - 5n/4,

where T(0) can be any number. d = -5/4

Assuming T(0) = 0, then first term

T(1) = 0 -5/4 = -5/4

Step-by-step explanation:

T(n) = T(0) + n*d

Let

S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240

S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220

S2 - S1

= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)

= (5+6+7+8 - 1 -2-3-4)d

= 4(4)d

= 16d

Since S2=220,  S1 = 240

220-240 = 16d

d = -20/16 = -5/4

Since T(0) has not been defined, it could be any number.

7 0
3 years ago
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