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3 years ago

13

Find the measure of ∠z.

1 answer:

Savatey [412]3 years ago

3 0

Answer:

B,(30)

Step-by-step explanation:

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A trophy is made up of copper and nickel. The ratio of their weights is 6:11. If the amount of copper in the trophy is 48 pounds

Ad libitum [116K]

6/11 = 48/X. First divide 48 by 6 (= 8) then multiply 11 by 8 (= 88). X=88 :) hope this helps

3 0

3 years ago

A haircut is 20 sales tax is 4.75 is 25 sufficient to cover the haircut cost with tax n tip %15 tip

zavuch27 [327]

Percentage of tip that needs to be given for hair cut = 15%
Amount of tip is calculated without sales tax.
Amount taken for the hair cut = 20
Amount of sales tax taken = 4.75
Then
Amount of tip given = (15/100) * 20
= 300/100
= 3
So the total amount required for the hair cut = 20 + 4.75 + 3
= 27.75
So 25 is insufficient amount to cover the hair cut cost with tip and sales tax. The actual amount required to cover the total cost is 27.75<span />

5 0

3 years ago

Use the alternative form of the derivative to find the derivative at x = c (if it exists). (If the derivative does not exist at

KIM [24]

Answer:

The derivative of the function does not exist.

Step-by-step explanation:

The alternative form of a derivative is given by:

$f'(c)= \lim_{x \to c} \dfrac{f(x)-f(c)}{x-c}$

Our function is defined as:

h(x)=|x+8|

i.e. h(x)= -(x+8) when x+8<0

and x+8 when x+8≥0

i.e. h(x)= -x-8 when x<-8

and x+8 when x≥-8

Hence now we find the derivative of the function at c=-8

i.e. we need to find the Left hand derivative (L.H.D.) and Right hand derivative (R.H.D) of the function.

The L.H.D at a point 'a' is calculated as:

$\lim_{x \to a^-} \dfrac{f(x)-f(a)}{x-a}\\\\=\lim_{h \to0} \dfrac{f(a-h)-f(a)}{a-h-a}= \lim_{h\to 0} \dfrac{f(a-h)-f(a)}{-h}$

Similarly R.H.D is given by:

$\lim_{x \to a^+} \dfrac{f(x)-f(a)}{x+a}\\\\=\lim_{h \to 0} \dfrac{f(a+h)-f(a)}{a+h-a}= \lim_{h\to 0} \dfrac{f(a+h)-f(a)}{h}$

Now for L.H.D we have to use the function h(x) =-x-8

and for R.H.D. we have to use the function h(x)=x+8

L.H.D.

we have a=-8

$\lim_{x \to (-8)^-} \dfrac{h(x)-h(-8)}{x-(-8)}\\\\= \lim_{h \to0} \dfrac{h(-8-h)-h(-8)}{-8-h-(-8)}= \lim_{h\to 0} \dfrac{h(-8-h)-h(-8)}{-h}$

= $\lim_{h \to 0} \dfrac{8+h-8-0}{-h}= \lim_{h \to 0}\dfrac{h}{-h}=-1$

similarly for R.H.D.

$\lim_{x \to (-8)^+} \dfrac{h(x)-h(-8)}{x-(-8)}\\\\=\lim_{h \to 0} \dfrac{h(-8+h)-h(-8)}{-8+h-(-8)}= \lim_{h\to 0} \dfrac{h(-8+h)-h(-8)}{h}$

$\lim_{h \to 0} \dfrac{-8+h+8-0}{h}=\lim_{h \to 0}\dfrac{h}{h}=1$

Now as L.H.D≠R.H.D.

Hence, the function is not differentiable.

4 0

3 years ago

Which property is illustrated by the following statement? If zxy=fde

inn [45]

The correct answer is the Transitive property

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On average you get like about 12 to 14 miles a gallon

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