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miskamm [114]
3 years ago
14

Calculate log 10.5 , Given that log 2 = 0.30, log 3 = 0.48 and log 7 = 0.85

Mathematics
1 answer:
Anni [7]3 years ago
5 0

Answer:

Step-by-step explanation:

log 2.5=log 21/2=log (3*7)/2=log3+log7-log 2=0.48+0.85-0.3=1.03

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Determine if the expression -8c-9c^4d^2−8c−9c
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Answer:

-8c-9c^4d^2-8c-9c is a polynomial of type binomial and has a degree 6.

Step-by-step explanation:

Given the polynomial expression

-8c-9c^4d^2-8c-9c

Group like terms

=-9c^4d^2-8c-8c-9c

Add similar elements: -8c-8c-9c=-25c

=-9c^4d^2-25c

Thus, the polynomial is in two variables and contains two, unlike terms. Therefore, it is a 'binomial' with two, unlike terms.

Each term has a degree equal to the sum of the exponents on the variables.

The degree of the polynomial is the greatest of those.

25c has a degree 1

-9c^4d^2 has a degree 6.   (adding the exponents of two variables 'c' and 'd').

Thus,

-8c-9c^4d^2-8c-9c is a polynomial of type binomial and has a degree 6.

4 0
3 years ago
HELP A.S.A.P!!!! The data to represent average test scores for a class of 16 students includes an outlier value of 78. If the ou
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When the outlier is removed The mean would increase.

<u>Step-by-step explanation:</u>

Outliers are the value that lies outside the set of data. i.e. the data doesn't fit in the group.

Removing outliers can affect mean more than median. Because outlier removal sometimes affect the median but in a small percentage or sometimes it will remain the same.

Let us prove, consider 16 values one with 78 and other 15 with values nearly 85, 84 that will give the mean value as 84.

78, 84, 82, 86, 84, 85, 83, 86, 82, 85, 84, 83, 86, 85, 86, 85.

Mean =\frac{Sum of the values}{Number of values}.

Mean =\frac{78+84+82+86+84+85+83+86+82+85+84+83+86+85+86+85}{16}.

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Mean =\frac{84+82+86+84+85+83+86+82+85+84+83+86+85+86+85}{15}.

Mean =\frac{1266}{15}.

Mean = 84.4.

The mean is increased.

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