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tekilochka [14]
3 years ago
7

the weather forecaster say that it is 200 C on Mars. Neptune is 7/10 as hot as mars. how hot is it in Neptune

Mathematics
1 answer:
ipn [44]3 years ago
5 0

Answer:

140 C

Step-by-step explanation:

<em>Write an equation</em> (n = neptune temp.; m = mars temp.)

n = 7/10 * m

<em>Plug in 200 degrees C for m</em>

n = 7/10 *200

<em>Simplify</em>

n = 140

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A brick layer is able to set 2.5 breaks in one minute how many bricks can you set an eight hours
frozen [14]

Answer:

<h2> In 8 hours he will set 1200 bricks</h2>

Step-by-step explanation:

In this problem, we are expected to estimate the number of bricks he can set in 8 hours.

let us convert hours to minutes we have

60 min make 1 hour

x min make 8 hours

cross multiply

x= 60*8

x= 480 min

We are assuming the same rate with which he sets 2.5 brick is the same as the rate with which he will set bricks for the 8 hours windows

so if the bricklayer sets

2.5 bricks in 1min

y bricks in 480 min

Cross multiply we have

y=2.5*480

y= 1200  bricks

hence in 8 hours, he will set 1200 bricks

5 0
3 years ago
For what values of x is the quantity x-7
Andreas93 [3]

positive = greater than 0.

Therefore we have the inequality:

x-7 > 0       |add 7 to both sides

x > 7

7 0
3 years ago
Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time
kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI  of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean                  x₁ =    25

Sample variance               s₁  = 27

Sample size                       n₁  = 45

Old machine

Sample mean                    x₂ =  23  

Sample variance               s₂  = 7,56

Sample size                       n₂  = 36

Test Hypothesis:

Null hypothesis                         H₀             x₂  -  x₁  = d = 0

Alternative hypothesis             Hₐ            x₂  -  x₁  <  0

CI = 90 %  ⇒  α =  10 %     α = 0,1      z(c) = - 1,28

To calculate z(s)

z(s)  =  ( x₂  -  x₁ ) / √s₁² / n₁  +  s₂² / n₂

s₁  = 27     ⇒    s₁²  =  729

n₁  = 45    ⇒   s₁² / n₁    = 16,2

s₂  = 7,56   ⇒    s₂²  = 57,15

n₂  = 36     ⇒    s₂² / n₂  =  1,5876

√s₁² / n₁  +  s₂² / n₂  =  √ 16,2  + 1.5876    = 4,2175

z(s) = (23 - 25 )/4,2175

z(s)  =  - 0,4742

Comparing z(s) and  z(c)

|z(s)| < | z(c)|  

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0
3 years ago
List these from least to greatest 1 1/5, -1.23, -1 1/6, 1.14
Sloan [31]

Answer:

of course 34

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Angie and Kenny play online video games. Angie buys 1 software package and 1 month of game play. Kenny buys 1 software package a
balandron [24]

The cost of one month of game play is $14

Step-by-step explanation:

Angie and Kenny play online video games

  • Angie buys 1 software package and 1 month of game play
  • Kenny buys 1 software package and 3 months of game play
  • Each software package costs ​$20
  • If their total cost is ​$96

We need to find the cost of one month of game play

∵ Angie buys 1 software package

∵ Kenny buys 1 software package

∵ Each software package costs ​$20

- Find the total cost of their software package

∴ The total cost of their software package = 20 × 1 + 20 × 1

∴ The total cost of their software package = 20 + 20 = 40

∴ The total cost of their software package is $40

Assume that the cost of one month of game​ play is $x

∵ The cost of one month of game​ play = x

∵ Angie buys 1 month of game play

∵ Kenny buys 3 months of game play

- Find the total cost of their game​ play

∴ The total cost of their game play = x × 1 + x × 3

∴ The total cost of their game play = x + 3x = 4x

∴ The total cost of their game play is $4x

∵ Their total cost is ​$96

- Add the costs of their software package and their game

   play and equate the sum by 96

∴ 40 + 4x = 96

- Subtract 40 from both sides

∴ 4x = 56

- Divide both sides by 4

∴ x = 14

The cost of one month of game play is $14

Learn more:

You can learn more about the word problems in brainly.com/question/10557938

#LearnwithBrainly

4 0
3 years ago
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