Question

Randy wants to either ride share to work or drive his own car to work, but it is impossible for Randy to ride share and drive his own car in one trip. If the probability that Randy ride shares is 0.22, and the probability that Randy drives his own car is 0.42, what is the probability that Randy ride shares or drives his own car to work?

Answer 1

Answer:

The probability that Randy ride shares or drives his own car to work is 0.64

Step-by-step explanation:

Given;

• Randy wants to either ride share to work or drive his own car to work

• but it is impossible for Randy to ride share and drive his own car in one trip

let the probability that Randy ride shares be A

let the probability that Randy drives his own car be B

P(A) = 0.22

P(B) = 0.42

The probability that Randy ride shares or drives his own car to work;

P = P(A) + P(B)

P = 0.22 + 0.42

P = 0.64

Therefore, the probability that Randy ride shares or drives his own car to work is 0.64