Hope this can help you. I tried to solve each one out and I tried to write notes on how I got the equation and the answer. Message me if you can't read something, my handwriting tends to be messy :)
There is a formula which employs the use of determinants and which helps us calculate the area of a triangle if the vertices are given as
. The formula is as shown below:
Area=
Now, in our case, we have: 
, and

Thus, the area in this case will become:
Area=
Therefore, Area=![\frac{1}{2}\times [[3(-1\times 1-(-5)\times 1]-3[3\times 1-(-2)\times 1]+1[3\times -5-2]]= \frac{1}{2}\times -20=-10](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5B%5B3%28-1%5Ctimes%201-%28-5%29%5Ctimes%201%5D-3%5B3%5Ctimes%201-%28-2%29%5Ctimes%201%5D%2B1%5B3%5Ctimes%20-5-2%5D%5D%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20-20%3D-10)
We know that area cannot be negative, so the area of the given triangle is <u>10 squared units</u>.
Answer:
K = 5m+y/x
Step-by-step explanation:
Let's solve for k.
y=kx+1m(2−7)
Step 1: Flip the equation.
kx−5m=y
Step 2: Add 5m to both sides.
kx−5m+5m=y+5m
kx=5m+y
Step 3: Divide both sides by x.
kx/x = 5m+y/x
Therefore, k = 5m+y/x
I think i can help with this prob
Answer:
-7x(x + 4)
Step-by-step explanation:
Not sure exactly what you're doing with this, but I know you're not solving it for x because there's no " = " there so I am assuming you're simplifying it as much as possible. I'm going with that.
First thing is to distribute through the parenthesis by multiplying 4x by 3x and then 4x by -7 to get:

Now combine like terms to get

The last thing you could do now is pull out what's common between each of those terms which is -7x. When you do that, you're left with
-7x(x + 4)