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3 years ago

Select the ordered pairs that satisfy the equation y=1/5x. Check all that apply.

Mathematics

2 answers:

Lyrx [107]3 years ago

7 0

C and E are the answers
C 2=1/5(10) 2=2
E -1=1/5(-5) -1=-1

exis [7]3 years ago

3 0

Answer:

Step-by-step explanation:

C 2=1/5(10) 2=2

E -1=1/5(-5) -1=-1

<h2>≈Delilah≈</h2>

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Use the F-scale measurements of tornadoes listed in the accompanying table. The range of the data is 4.0. Use the range rule of

Tcecarenko [31]

Answer:

Within 0.5 of ;

is not ;

Step-by-step explanation:

Given the data:

The actual standard deviation, = 1

;

The range rule of thumb to estimate the value if standard deviation is ;

Estimated standard deviation = Range / 4

The range = (maximum - minimum) values

The estimated standard deviation = 4 / 4 = 1

Hence, the estimated standard deviation is with 0.5 of the actual standard deviation, Thus, the estimated standard deviation is not substantially different from the actual standard deviation.

4 0

3 years ago

11 PTS! 5 STARS! THANKS ON PROFILE AND QUESTION1 FIRST TO ANSWER ALL 5 GETS BRAINLIEST!

denis-greek [22]

1) Answer: 21
As y varies directly with x, this means that the ratio y/x is always a constant.
In other words, the equation can be written as y = kx, where k is a constant term.

Thus, $-\frac{14}{4} = -\frac{y}{6}$
y = 21

2) Answer: C
Exactly the same process as above.
Here's another method:
25 = k(140)
k = 25/140 = 5/28

Thus, when y = 36, 36 = kx
36 = 5/28(x)
36 * 28/5 = x; x = 201.6

3) 9 = k(12)
9/12 = k and k = 3/4

4) On the graph, it hits y = 1 at x = 4.
Thus, we can rewrite the equation as:
y = (1/4)x, where the constant term is 1/4

5) y = kx
The distance represents the x-ordinates, and the time represents the y-ordinates.

9.5/475 = 0.02
4 = 0.02(x), in hours.
x = 200 miles.

4 0

3 years ago

If y-3x=9, 7x+y=25, what is the value of x and y?

lianna [129]

$\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?$

$\bold{\rm{Solution}} \text{: We'll solve this by substitution method}$

$\dashrightarrow y - 3x = 9 \\ \\ \dashrightarrow \boxed{y = 9 + 3x } \qquad .. \sf eq(1)$

$\text{we got the value of y now getting the value of x}$

$\looparrowright 7x + y = 25 \\ \\ \looparrowright 7x = 25 - y \\ \\ \looparrowright \boxed{x = \frac{25 - y}{7}} \qquad .. \sf eq(2)$

$\text{Now, putting y = 9 + 3x in eq(2)}$

$\hookrightarrow x = \frac{25 - y}{7} \\ \\ \hookrightarrow x = \frac{25 - 9 + 3x}{7} \\ \\ \hookrightarrow 7x = 25 - 9 + 3x \\ \\ \hookrightarrow 7x - 3x = 16 \\ \\ \hookrightarrow 4x = 16 \\ \\ \hookrightarrow x = \frac{16}{4} \\ \\ \star \quad \boxed{ \green{ \frak{ x = 4}}}$

$\text{Now we know the value of x, for getting y we need to put x in eq(1)}$

$: \implies y = 9 + 3x \\ \\ : \implies y = 9 + 3(4) \\ \\ : \implies y = 9 + 12 \\ \\ \star \quad \boxed{\frak{ \green{y = 21}}}$

$\text{Hence, values of x and y are} \: \frak{ \green{4}} \: \text{and} \: \frak{ \green{21}} \: \text{respectively}.$

4 0

2 years ago

How to find height of a triangular prism where length is 9, width is 3.5, and height is unknown. Volume is 50.4, and explain ans

riadik2000 [5.3K]

*The width in your question - I assumed it is refers to the height of the triangle base.

Volume of a triangle prism = base area x height

The base is a triangle:
Volume of a triangle prism = (1/2 x base x height₁) x height₂

Plug in the values and solve for height₂:

50.4 = (1/2 x 9 x 3.5) x height

50.4 = 15.75 x height

height = 50.4 ÷ 15.75

height = 3.2 units

-----------------------------------------
Answer: Height = 3.2 units
-----------------------------------------

5 0

4 years ago

A post is supported by two wires (one on each side going in oppositedirections) creating an angle of 80° between the wires. The

Vladimir [108]

Using the Sine rule,

$\frac{\sin A}{A}=\frac{\sin B}{B}=\frac{\sin C}{C}$ $\begin{gathered} \text{Let A = 14m,} \\ Substituting the variables into the formula,Where the length of the wires are, AP = xm and BP = ym[tex]\begin{gathered} \frac{\sin80^0}{14}=\frac{\sin40^0}{x} \\ \text{Crossmultiply,} \\ x\times\sin 80^0=14\times\sin 40^0 \\ Divide\text{ both sides by }\sin 80^0 \\ x=\frac{14\sin40^0}{\sin80^0} \\ x=9.14m \end{gathered}$

Hence, the length of wire AP (x) is 9.14m.

For wire BP (y)m,

Sum of angles in a triangle is 180 degrees,

$A^0+P^0+B^0=180^0$ $\begin{gathered} \text{Where A}^0=\text{ unknown,} \\ P^0=80^0\text{ and,} \\ B^0=40^0 \\ A^0+80^0+40^0=180^0 \\ A^0+120^0=180^0 \\ A^0=180^0-120^0 \\ A^0=60^0 \end{gathered}$

Using the side rule to find the length of wire BP,

$\begin{gathered} \frac{\sin 60^0}{y}=\frac{\sin 80^0}{14} \\ \text{Crossmultiply,} \\ y\times\sin 80^0=14\times\sin 60^0 \\ \text{Didive both sides by }\sin 80^0 \\ y=\frac{14\times\sin 60^0}{\sin 80^0} \\ y=12.31m \end{gathered}$

Hence, the length of wire BP (y) is 12.31m

Therefore, the length of the wires are (9.14m and 12.31m).

4 0

1 year ago