Question

Tre and Hector want to calculate the maximum possible throw at this field.

Answer 1

Answer:

$d=455.38~units$

Step-by-step explanation:

The coordinates of the dead center of the field, $D\equiv (322,322)$

Home base in a coordinate system is always the origin, $O\equiv(0,0)$

The center fielder threw the ball form the dead center to the home base, hence the distance of throw:

$d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$d=\sqrt{(322-0)^2+(322-0)^2}$

$d=455.38~units$