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Dmitry_Shevchenko [17]
3 years ago
15

Solve by completing the square 3x^2-7x-1

Mathematics
1 answer:
docker41 [41]3 years ago
3 0

Answer:

x=\frac{7+\sqrt{61}}{6},\:x=\frac{7-\sqrt{61}}{6}

Step-by-step explanation:

a=3,\:b=-7,\:c=-1:\quad x_{1,\:2}=\frac{-\left(-7\right)\pm \sqrt{\left(-7\right)^2-4\cdot \:3\left(-1\right)}}{2\cdot \:3}

x=\frac{7+\sqrt{61}}{6},\:x=\frac{7-\sqrt{61}}{6}

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