$f(x)=\dfrac{x-5}{x^2-1}\\\\\text{the horizontal asymptotes}\\\\x^2-1=0\to x^2=1\to x=\pm\sqrt1\to x=-1\ \wedge\ x=1\\\\\text{the vertical asymptotes}\\\\y=\lim\limits_{x\to\pm\infty}\dfrac{x-5}{x^2-1}=\lim\limits_{x\to\pm\infty}\dfrac{\frac{x}{x^2}+\frac{5}{x^2}}{\frac{x^2}{x^2}-\frac{1}{x^2}}=\dfrac{0+0}{1-0}=0$

Answer: <span>B) x = 1, x = -1, y = 0</span>

8 0

2 years ago

Find x. Give your answer in the

garri49 [273]

Answer:

x = 4

Step-by-step explanation:

sin 30 = x/8

0.5 = x/8

x = 4

7 0

2 years ago

Hillside orchard grows Fiji apples and Gala apples. There are 160 Fiji apple trees and 120 Galla apple trees in the orchard. Hil

Paul [167]

Answer:

190

Step-by-step explanation:

160 - 120 = 40

120 + 30 = 150

150 + 40 = 190

7 0

2 years ago

PLEASE ANSWER ASAP!! it might be me just being stupid but I was given a question on sequences. I was given the sequence 2,8,14,2

natulia [17]

I think ur homework sheet is wrong the difference is definitely 6

6 0

2 years ago