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stiv31 [10]
3 years ago
5

Katrina is asked to simplify the expression Negative 3 a minus 4 b minus 2 (5 a minus 7 b).

Mathematics
2 answers:
yuradex [85]3 years ago
7 0

Answer:

-13a+10b

Step-by-step explanation:

-3a- 4b- 2(5a-7b)

OPEN THE BRACKET

-3a-4b-10a+14b

CLT

-3a-10a-4b+14b

-13a+10b. (ANSWER)

NeTakaya3 years ago
6 0

Answer:

-13a+10b

Step-by-step explanation:

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The points on the graphs represent relations. Classify these relations according to whether or not they are functions.
tiny-mole [99]
<h2>Answer:</h2>

A function f from a set A to a set B is a relation that assigns to each element x in the set A exactly one element y in the set B. The set A is the domain (also called the set of inputs) of the function and the set B contains the range (also called the set of outputs).

  • First figure is not a function because the x-coordinate 2 has more than one element in the set of outputs.

  • Second figure is a function because this each element x in the set A is assigned to exactly one element y in the set B.

  • Third figure is not a function because the x-coordinates -1, 1 and 2 have assigned more than one element in the set of outputs.

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Step-by-step explanation:

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3 years ago
Crude oil imports to one country from another for 2009–2013 could be approximated by the following model where t is time in year
DIA [1.3K]

Answer:

Import in 2012 was the greatest

Step-by-step explanation:

Given

l(t) = -33t² + 800t - 3000

9 ≤ t ≤ 13

Required

Determine the year with highest import.

To do this we simply substitute the values of t from 9 to 13 in the given function.

When t = 9

l(t) = -33t² + 800t - 3000

l(9) = -33 * 9² + 800 * 9 - 3000

l(9) = -33 * 81 + 800 * 9 - 3000

l(9) = -2673 + 7200 -3000

l(9) = 1527

When t = 10

l(10) = -33 * 10² + 800 * 10 - 3000

l(10) = -33 * 100 + 800 * 10 - 3000

l(10) = -3300 + 8000 - 3000

l(10) = 1700

When t = 11

l(11) = -33 * 11² + 800 * 11 - 3000

l(11) = -33 * 121 + 800 * 11 - 3000

l(11) = -3993 + 8800 - 3000

l(11) = 1807

When t = 12

l(12) = -33 * 12² + 800 * 12 - 3000

l(12) = -33 * 144 + 800 * 12 - 3000

l(12) = -4752 + 9600 - 3000

l(12) = 1848

When t = 13

l(13) = -33 * 13² + 800 * 13 - 3000

l(13) = -33 * 169 + 800 * 13 - 3000

l(13) = -5577 + 10400 - 3000

l(13) = 1823

Comparing the values of l(t) for the range of t = 9 to 13,

The highest value of l(t) is:

l(12) = 1848

Hence, the year with the highest import is 2012

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