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Shkiper50 [21]
3 years ago
5

A stack of cards is numbered 1 to 21. Kelly pulls one card from the stack. What is the best approximation for the probability th

at the card is an even number?
5%
21%
48%
52%
Mathematics
1 answer:
ASHA 777 [7]3 years ago
8 0
The correct answer is 48%

There are 10 even numbers from 1 to 21.

That makes the probability of an even number 10 out 21.

10 / 21 x 100 = 48%
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Ymorist [56]
D = m / V 
<span>m = 1.26 g </span>
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<span>so </span>
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<span>and this corresponds to choice (a)

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1 + tanx / 1 + cotx =2
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Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

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Step-by-step explanation:

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1 + cot(x) + tan(x) = 2

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1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

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Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

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or tan(x) - 1/2 = -(i sqrt(3))/2

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x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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trasher [3.6K]

Step-by-step explanation:

Solution:

Given:-

(X+y,y+3)=(6,2y)

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8 0
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