Pls this is timed thank you

Mathematics

2 answers:

mihalych1998 [28]4 years ago

6 0

Answer:

Step-by-step explanation:

$\frac{4}{Sin25*} = \frac{x}{Sin90*}$

$\frac{4Sin90*}{Sin25*} = x$

$x=\frac{4}{sin25*}$

$x=9.46480\dots$

$x=9$

statuscvo [17]4 years ago

4 0

I believe that is Khan academy from what I can see so no no I don’t believe it is timed, they do know all the timings but that won’t affect the score

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Check down the image that’s give below

gregori [183]

<u>Solution</u><u>:</u>

$\frac{3x}{ {x}^{2} + 6x + 9} + \frac{x + 3}{ {x}^{2} - 9 }$

In the first fraction, we have to factorise the denominator using (a + b)² = a² + 2ab + b². And in the second fraction, we have to factorise the denominator using a² - b² = (a - b)(a + b) identity.

$= \frac{3x}{ {(x)}^{2} + 2(x)(3) + ( {3)}^{2} } + \frac{x + 3}{(x)^{2} - (3)^{2} } \\ = \frac{3x}{(x + 3) ^{2} } + \frac{x + 3}{(x + 3)(x - 3)}$

From the second fraction, cancel out from both sides (x + 3), the we get:

$= \frac{3x}{(x + 3) ^{2} } + \frac{1}{(x - 3)} \\ = \frac{3x(x - 3) + 1(x + 3) ^{2} }{(x + 3)^{2} (x - 3)} \\ = \frac{3x ^{2} - 9 x+ {x}^{2} + 6x + 9}{ {(x + 3)}^{2} (x - 3)} \\ = \frac{ {4x}^{2} - 3x + 9}{(x + 3)(x + 3)(x - 3)}$