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Anna35 [415]
3 years ago
5

What simple interest would be earned if $5000 is invested at 9% for 9 months ?

Mathematics
1 answer:
mestny [16]3 years ago
5 0

Answer:

about $10859.47 if you're talking total but about $5859.47 if you're talking about how much more than the initial value

Step-by-step explanation:

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Is the following exponential graph increasing or decreasing? If it is, what exponent problem is it? Explain.
Akimi4 [234]
It is increasing and the exponential problem should be 5e^x-8
3 0
2 years ago
HELP; PLZZZ GIVING 20 BRAINLIEST PLZZZ.
Andrew [12]

Answer:

Step-by-step explanation:

In the equation y=kx+1, k is the slope and 1 is the y-intercept.

To find the slope, use the formula k=y2-y1/x2-x1. To use this formula, you need two points. The first point, point M, is given to you. The second point can be the y-intercept, point (0, 1). Now, apply the formula to find the slope: k=3-1/1-0

k=2/1

k=2

We now have the equation y=2x+1.

The next step is to graph the line.

First, graph the y-intercept. Should look something like this: (star represents point. the point is on (0, 1).)

           |

           |

           *

------------------------------

           |

           |        

Then, use the slope to find your second point: (the point is on (1, 3)).

           |    *

           |

           *

------------------------------

           |

           |        

Draw a line through those two points and you have your answer!

6 0
2 years ago
Please help me!!!!!!!!!!
Kipish [7]

Answer:

80 is the kilometers question

8 0
2 years ago
Use decimals and fractions in the same equation showing the Commutative Property. Repeat for the Associative Property.
Anna71 [15]

For Commutative Property of Addition

Let us take a decimal number 2.14 and a fraction \frac{5}{20}

Now, according to the Commutative property of Addition:

For any two numbers a and b :

a+b = b+a

So, for 2.14 and \frac{5}{20}

Let us add

2.14+\frac{5}{20}  = \frac{214}{100}  +\frac{5}{20}

                                   =\frac{214}{100}  + \frac{5 \times 5}{20 \times 5} \\ \\=\frac{214}{100}  + \frac{25}{100} \\ \\= 2.14 + 0.25 \\ \\ = 2.39

Also,

\frac{5}{20} + 2.14  = \frac{5}{20} + \frac{214}{100}

                                     = \frac{5 \times 5}{20 \times 5} +\frac{214}{100} \\ \\= \frac{25}{100}  + \frac{214}{100} \\ \\=  0.25 + 2.14 \\ \\ = 2.39

Therefore, 2.14+\frac{5}{20} = \frac{5}{20} + 2.14

Hence,  Commutative Property of Addition is satisfied.


For Associated Property of Addition

Let us take two same decimal numbers 2.14 , 7.25 and a fraction \frac{5}{20}

Now, according to the Associated property of Addition:

For any three numbers a, b  and  c

a + (b+c) =(a+b) + c

So, for 2.14 , 7.25 and \frac{5}{20}

The Left hand side:

a + (b+c)

2.14 + (7.25 + \frac{5}{20}) = 2.14 + (\frac{725}{100} + \frac{5 \times 5}{20\times 5})

                                                         = 2.14 + (\frac{725}{100} + \frac{25 }{100})

                                                         = 2.14 + (\frac{750}{100} )

                                                        = \frac{214}{100} + \frac{750}{100}

                                                         = \frac{964}{100}

                                                        =9.64


The Right hand side:

(a + b )+c

(2.14 + 7.25 )+ \frac{5}{20}= ( 9.39 ) + \frac{5 }{20}

                                                = 9.39  + \frac{5 \times 5 }{20 \times 5}

                                                = 9.39  + \frac{25}{100}

                                                = 9.39  + 0.25

                                                = 9.64


Thus,

(2.14 + (7.25 + \frac{5}{20} )= (2.14 + 7.25 )+ \frac{5}{20}

Therefore, 2.14+\frac{5}{20} = \frac{5}{20} + 2.14

Hence,  Associative Property of Addition is satisfied.




8 0
3 years ago
Find the 59th term of the following arithmetic sequence. 15, 23, 31, 39
m_a_m_a [10]

15~~,~~\stackrel{15+8}{23}~~,~~\stackrel{23+8}{31}~~,~~\stackrel{31+8}{39}~~,~~...~\hspace{10em}\stackrel{common~difference}{d=8} \\\\[-0.35em] ~\dotfill\\\\ n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\stackrel{\textit{term position}}{59}\\ a_1=\stackrel{\textit{first term}}{15}\\ d=\stackrel{\textit{common difference}}{8} \end{cases} \\\\\\ a_{59}=15+(59-1)8\implies a_{59}=15+472-8\implies a_{59}=479

4 0
2 years ago
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