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3 years ago

Which polynomial correctly combines the like terms and expresses the given polynomial in standard form?

Mathematics

2 answers:

topjm [15]3 years ago

5 0

Answer:

9xy^3 – 4y^4 – 10x^2 * y^2 + x^3 * y + 3x^4 + 2x^2 * y^2 – 9y^4

Step-by-step explanation:

Arranging the different terms of the polynomial:

3x^4 + x^3 * y – 10x^2 * y^2 + 2x^2 * y^2 + 9xy^3 – 4y^4 – 9y^4

3x^4 + x^3 * y – 8x^2 * y^2 + 9xy^3 – 13y^4

Therefore, the third choice is the correct answer

STatiana [176]3 years ago

4 0

Answer:

D. $3x^4 + x^3y - 8x^2y^2 + 9xy^3 - 13y^4$

Step-by-step explanation:

$9xy^3 - 4y^4 - 10x^2y^2 + x^3y + 3x^4 + 2x^2y^2 - 9y^4 =$

$= 9xy^3 - 13y^4 - 8x^2y^2 + x^3y + 3x^4$

$= 3x^4 + x^3y - 8x^2y^2 + 9xy^3 - 13y^4$

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Find 3.96/0.7 to the nearest tenth

aliya0001 [1]

$3.96:0.7= \frac{\big{3.96}}{\big{0.7}} =\frac{\big{3.96\cdot10}}{\big{0.7\cdot10}} =\frac{\big{39.6}}{\big{7}} \approx5.7$

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3 years ago

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choose the equation of the horizontal line that passes through the point (−2, −1). y = −1 y = −2 x = −2 x = −1

NNADVOKAT [17]

For a horizontal line, gradient is zero;
y=mx+c
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4 years ago

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lions [1.4K]

Answer:

pizza, or sandwiches

Step-by-step explanation:

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3 years ago

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If the confidence level is 90%, find the Margin of sampling error. The population is normally distributed, the sample size is 15

charle [14.2K]

Answer:

$ME = 1.761* \frac{5}{\sqrt{15}}=2.273$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X= 75$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=5 represent the sample standard deviation

n=15 represent the sample size

Solution to the problem

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=15-1=14$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,14)".And we see that $t_{\alpha/2}=1.761$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$

And if we replace the values we got:

$ME = 1.761* \frac{5}{\sqrt{15}}=2.273$

6 0

3 years ago

Find the answer<br> 29°<br> 36°<br> 49°<br> 61°

Alla [95]

<h3>Answer: Choice A, 29 degrees</h3>

Central angle CBA is a right angle, so it is 90 degrees. This means the arc measure from A to C, following the shortest path on the curve, is 90 degrees. This is minor arc CA. A minor arc is one that is less than 180 degrees in measure.

We want to find the measure of minor arc DE. This is the last piece of the puzzle, so to speak, that forms the entire arc ACD. This arc is 180 degrees because AD is a diameter.

So,

(minor arc DE) + (minor arc EC) + (minor arc CA) = arc ACD

x + 61 + 90 = 180

x + 151 = 180

x + 151 - 151 = 180 - 151 .... subtract 151 from both sides

x = 29

Minor arc DE is 29 degrees.

Check out the attached image below if you're still stuck. Hopefully the image clears any confusion you may have.

5 0

4 years ago