All categories

3 years ago

The equation having null set as its solution set is

Mathematics

1 answer:

KIM [24]3 years ago

4 0

Answer:

B) x = e^x

Step-by-step explanation:

The graphs of y = e^x and y = x never intersect, so the solution set will be the empty (null) set for ...

x = e^x

_____

There is one intersection of y=x with cos(x) and with sin(x). There are an infinite number of solutions for x = tan(x).

You might be interested in

Plz just give the eqution.

Nina [5.8K]

Answer:

16 = <u>3x</u>

Step-by-step explanation:

It is an equilateral triangle. The formula for the perimeter of an equilateral triangle is P = 3a.

3 0

3 years ago

Give me the solution of this algebra<br> 1) a^2 + 3a + 1

GuDViN [60]

Answer:

slader app helps alot

Step-by-step explanation:

5 0

3 years ago

Eli wants to combine 0.5 gallon of a 10% acid solution with some 35% acid solution to make a 15% acid solution. How much of the

emmainna [20.7K]

Answer:

<h3> 0.125 galon of 35% acid solution</h3>

Step-by-step explanation:

0.5 gallon of a 10% acid solution

10%•0.5 = 0.05 gallon of acid in that solution

x gallon of 35% acid solution

35%•x = 0.35x gallons of acid in that solution

0.05 + 0.35x total of gallons of acid in both solutions

(0.5+x) gallons of 15% acid solution

15%(0.5+x) = 0.15(0.5+x) gallons of acid in that solution

the amount of gallons of acid didn't change after mixing, so:

0.05 + 0.35x = 0.15(0.5 + x)

0.05 + 0.35x = 0.075 + 0.15x

0.35x - 0.15x = 0.075 - 0.05

0.2x = 0.025

×5 ×5

x = 0.125

8 0

3 years ago

Read 2 more answers

3 (182 + 2) – 172 = -17

IrinaK [193]

Answer:

380≠−17

Step-by-step explanation:

3(182+2)−172 ?= −17

380≠−17

5 0

3 years ago

Read 2 more answers

Perchlorate is a chemical used in rocket fuel. People who live near a former rocket-testing site are concerned that perchlorate

ser-zykov [4K]

Answer:

$H_1 : \mu > 24.5$

Step-by-step explanation:

From the given information:

The sample size is 28

The population mean is 24.5 (ppb)

The sample mean is 225.3 (ppb)

Thus, the null and the alternative hypothesis can be computed as:

Null hypothesis:

$H_o : \mu \le 24.5$

Alternative hypothesis:

$H_1 : \mu > 24.5$

8 0

3 years ago