Ask question

Ask question

All categories

2 years ago

5

Log(5)(x+4)+log(5)(x+2)=log(5)(7x+10)

1 answer:

inessss [21]2 years ago

7 0

<span>Combine the logarithms first: log5(4x+3)-log5(x-1). Since it's subtract, divide the two.

log5((4x+3)/(x-1))=2

Make both sides the exponent of five. 5^log5 cancels out.

5^(log5(4x+3/x-1))=5^2

4x+3/x-1=25

Multiply both sides by (x-1) to get rid of it under 4x+3.

(x-1)4x+3/x-1=25(x-1)

4x+3=25x-25

Now subtract 4x from both sides AND add 25 to both sides. This way you'll have all the x's by itself.

28=21x

Divide both sides by 21.

28/21=x

x=1.33333333333...

</span>

You might be interested in

Math! Answer to 1&2?

Jobisdone [24]

Answer:

the number 1 is going to be B and number 2 is going to be C

Step-by-step explanation:

hope this helps

5 0

2 years ago

The perimeter of a rectangle is 254 cm. Its length is 55 cm. What is the width of the rectangle with a variable?

Elanso [62]

Answer:

Rectangle w=72

Step-by-step explanation:

Rectangle

Solve for

width

w

=

72

cm

l

Length

cm

P

Perimeter

cm

5 0

2 years ago

Rectangle ABCD was dilated to create rectangle A'B'C'D. Triangle A B C D is dilated to form triangle A prime B prime C prime D.

Julli [10]

Answer:

$AB = 6$

Step-by-step explanation:

Given

$BC = 3.8$

$A'B' = 15$

$B'C' = 9.5$

Required

Determine the length of AB

Because A'B'C'D is a dilation of ABCD, then the following relationship must exist:

$A'B' : AB = B'C' : BC$

Substitute values for A'B', B'C' and BC

$15 : AB = 9.5 : 3.8$

Express the ratio as fractions:

$\frac{AB}{15} = \frac{3.8}{9.5}$

Multiply through by 14

$15 * \frac{AB}{15} = \frac{3.8}{9.5} * 15$

$AB = \frac{3.8}{9.5} * 15$

$AB = \frac{3.8* 15}{9.5}$

$AB = \frac{57}{9.5}$

$AB = 6$

8 0

2 years ago

Read 2 more answers

What are the approximate values of the non-integral roots of the polynomial equation?

irga5000 [103]

Answer:

-4, -2, -3-2i, -3+2i

Step-by-step explanation:

The of the polynomial equation are those values of x, for which f(x)=0.

Consider equation

$f(x)=0\\ \\(x^2+6x+8)(x^2+6x+13)=0$

By zero product property,

$x^2+6x+8=0\ \text{or}\ x^2+6x+13=0$

Solve each equation:

1. $x^2+6x+8=0$

$D=6^2-4\cdot 8=36-32=4\\ \\x_{1,2}=\dfrac{-6\pm \sqrt{4}}{2}=\dfrac{-6\pm 2}{2}=-4,\ -2$

2. $x^2+6x+13=0$

$D=6^2-4\cdot 13=36-52=-16=16i^2\\ \\x_{1,2}=\dfrac{-6\pm \sqrt{16i^2}}{2}=\dfrac{-6\pm 4i}{2}=-3-2i,\ -3+2i$

5 0

2 years ago

Read 2 more answers

The difference between two integers is at least 14. The smaller integer

egoroff_w [7]

The difference between two integers is at least 14. The smaller integer is 2. What is the larger integer?

<h3><u>Answer:</u></h3>

The largest integer is 16

<h3><u>Solution:</u></h3>

Given that difference between two integers is at least 14

The smaller integer is 2

To find: largest integer

Let the smallest integer be "y" and largest integer be "x"

smallest integer = x = 2

difference between two integers is at least 14

So, y - 2 $\geq$ 14

y $\geq$ 14 + 2

y $\geq$ 16

Thus the largest integer is 16

5 0

2 years ago