Log(5)(x+4)+log(5)(x+2)=log(5)(7x+10)

1 answer:

7 0

Combine the logarithms first: log5(4x+3)-log5(x-1). Since it's subtract, divide the two.

log5((4x+3)/(x-1))=2

Make both sides the exponent of five. 5^log5 cancels out.

5^(log5(4x+3/x-1))=5^2

4x+3/x-1=25

Multiply both sides by (x-1) to get rid of it under 4x+3.

(x-1)4x+3/x-1=25(x-1)

4x+3=25x-25

Now subtract 4x from both sides AND add 25 to both sides. This way you'll have all the x's by itself.

28=21x

Divide both sides by 21.

28/21=x

x=1.33333333333...

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The table represents a function. A 2-column table with 5 rows. The first column is labeled x with entries negative 6, 7, 4, 3, n

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Answer:

-2 is an output of the function.

Step-by-step explanation:

The given table is as follows:

$\left[\begin{array}{cc}{x}&f(x)\\-6&8\\7&3\\4&-5\\3&-2\\-5&12\end{array}\right]$

Here, the values written on the left side of table i.e. values of $x$ are known as the domain values or input values to a function.

The values written on the right side of table i.e. values of $f(x)$ are known as the range values or output values of the function $f(x)$ .