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e-lub [12.9K]
3 years ago
10

There were 23 students running in a race. How many different arrangements of first, second, and third place are possible?

Mathematics
1 answer:
Alex787 [66]3 years ago
7 0

Answer:

10626 different arrangements

Step-by-step explanation:

As we have a total of 23 students and we want to form groups of 3, where the order of the 3 students matters, we can solve this problem using a permutation of 23 choose 3.

The formula for a permutation of n choose p is:

P(n,p) = n! / (n-p)!

So, using n = 23 and p = 3, we have:

P(23,3) = 23! / (23-3)! = 23! / 20! = 23 * 22 * 21 = 10626

So we have a total of 10626 different arrangements of first, second and third place.

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3n *power 2 +10n+7 how to factories and pls tell with solution
tankabanditka [31]

Answer:

(n + 1)(3n + 7)

Step-by-step explanation:

3n² + 10n + 7

Consider the factors of the product of the n² term and the constant term which sum to give the coefficient of the n- term.

product = 3 × 7 = 21 and sum = + 10

The factors are + 3 and + 7

Use these factors to split the n- term

3n² + 3n + 7n + 7 ( factor the first/second and third/fourth terms )

3n(n + 1) + 7(n + 1) ← factor out (n + 1) from each term

= (n + 1)(3n + 7) ← in factored form

5 0
3 years ago
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Answer:

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5 0
3 years ago
A town has a population of 2000 and grows at 4% every year what will be the population after 15 years to the nearest whole numbe
fomenos

To begin lets say year one the population is 2,000

assume this in percent we can say that 2,000=100%

at the end of this year the population will have grown by 4% meaning that

100%+4% will be the new population =104%

but we know that 100%=2,000 so what about 104%=X?

so (104*2000)/100=2,080

So year 1 the population will have grown by 80 people amounting to 2080 people.

Now do it manually year by year until we reach the 15th year. i will help you up to year 3

2nd year= (2080*104)/100=2163.2

3rd year= (2163*104)/100=2249.728

(If you have more complex questions reach me at essaywritingpool.com)


5 0
3 years ago
HELP WILL MARK BRAINLIEST PLEASE ANSWER ALL THREE
Anna11 [10]
Five is b
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Seven is a
Goood day now
5 0
3 years ago
FIRST ANSWER GET BRAINLEST
liraira [26]

Let's call x the price of a box of slime.

Gianna spent 4 × $58 for art supplies so 4(58) + 8x all together.  We have

392 ≤  4(58) + 8x ≤ 472

We can work with both inequalities at once.  4(58)=232 so we subtract that from all three sides.

160 ≤ 8x ≤ 240

Divide all three sides by 8, a positive number so the inequalities don't flip.

20 ≤ x ≤ 30

Answer: Least: $20, Most: $30


5 0
3 years ago
Read 2 more answers
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