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Table (A) represents the parabola y = x² - 6x in which the parabola opens and the y-intercept is (0, 0) table (A) is the correct choice.
<h3>What is a parabola?</h3>It is defined as the graph of a quadratic function that has something bowl-shaped.
We have the tables shown in the picture.
We know the quadratic form of a parabola is:
y = ax² + bx + c
If a > 0 the parabola opens
In the equation:
y = x² - 6x
1 > 0 the parabola opens and y-intercept is:
y = 0 (plug x = 0 in the given equation)
a = 1, b = -6, and c = 0
Thus, table (A) represents the parabola y = x² - 6x in which the parabola opens and the y-intercept is (0, 0) table (A) is the correct choice.
Learn more about the parabola here:
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Answer:
0
Step-by-step explanation:
This equation is in "vertex form," meaning that you can identify the vertex and other features of the graph from the equation.
y = a(x -h)² +k . . . . . the vertex is (h, k); the vertical scale factor is "a"
Comparing to your equation, you see ...
a = -1/2, h = 3, k = -1
The vertex is (h, k) = (3, -1). The vertical scale factor is negative.
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This tells you the graph opens downward (the scale factor is negative), and the vertex (maximum point) is below the x-axis. (It has a negative y-coordinate.)
Because it start below the x-axis and goes down from there, the graph does not intersect the x-axis. There are zero (0) x-intercepts.
